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Eva8 [605]
3 years ago
5

Assets Liabilities Net Worth Reserves $120,000 Checkable Deposits $300,000 Loans 140,000 Stock Shares 200,000 Securities 40,000

Property 200,000 The accompanying balance sheet is for the First Federal Bank. Assume the required reserve ratio is 20 percent. If the original bank balance sheet was for the whole commercial banking system rather than a single bank, loans and deposits could have been expanded by a maximum of
Business
1 answer:
bulgar [2K]3 years ago
3 0

Answer:

$300,000

Explanation:

Money Multiplier = 1 / Required Reserve Ratio

Money Multiplier = 1 / 0.20

Money Multiplier = 5

Reserve requirement will be 20% of $300,000 (Checkable Deposits)

Reserve requirement = $60,000

Excess Reserves = Reserve - Required Reserve

Excess Reserves = $120,000 - $60,000

Excess Reserves = $60,000

Expansion in loans and deposits will be: Excess reserves * money multiplier

= $60,000 * 5

= $300,000

So, if the original bank balance sheet was for the whole commercial banking system rather than a single bank, loans and deposits could have been expanded by a maximum of $300,000.

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Answer:

Bad debt expense (w/o allowance) = $2,875

Bad debt expense ( with allowance) = $2,675.

Explanation:

According to the scenario, the given data are as follows:

Net credit sales = $115,000

Uncollectible percentage = 2.5%

So, we can calculate the bad debt expense without Allowance for doubtful accounts by using following method:

Bad debt expense ( W/o allowance) = $115,000 × 2.5%

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After Allowance for doubtful expense

Bad debt expense = $2,875 - $200

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<u><em>Answer:</em></u>

<u><em>1. Likely the price of the stock either goes up or falls</em></u>

<u><em>2. There is no need for a stop loss order in this scenario.</em></u>

<u><em>3. 5412541.2</em></u>

<u>Explanation</u>:

1. Stock market prices are often  unstable, prices can be up today, the next day they are low.

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3. A 10% Stop loss price would have been the idea order price rather than the ​$53.7353.73​.

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Answer:

EV of node 4 = 0.6×5 + 0.4×0 = 3

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EV of node 2 = (0.8×5 + 0.2×3 ) - 3

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