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love history [14]
3 years ago
5

How would kinetic energy of the dominoes be affected if the first domino did not hit the second one?(((20 points)))

Chemistry
1 answer:
Semenov [28]3 years ago
5 0

Answer:

Not affected.

Explanation:

Kinetic energy of the dominoes not affected if the first domino did not hit the second one because no kinetic energy is lost due to no collision. If the first domino hit the second one, its kinetic energy decreases and changes in other form of energy such as heat and sound energy etc. But when there is no collision occur, then there is no change in the kinetic energy of dominoes.

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If you had 6 mol of oxygen and 12 mol of mercury, what would be the limiting reactant? show your work
gayaneshka [121]

The limiting reactant between the reaction of 6 moles of oxygen and 12 moles of mercury is mercury (Hg)

<h3>Balanced equation </h3>

4Hg + O₂ —> 2Hg₂O

From the balanced equation above,

4 moles of Hg reacted with 1 mole of O₂

<h3>How to determine the limiting reactant</h3>

From the balanced equation above,

4 moles of Hg reacted with 1 mole of O₂

Therefore,

12 moles of Hg will react with = 12 / 4 = 3 moles of O₂

From the above calculation, we can see that only 3 moles of O₂ out of 6 moles given is required to react completely with 12 moles of Hg.

Thus, Hg is the limiting reactant and O₂ is the excess reactant .

Learn more about stoichiometry:

brainly.com/question/14735801

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3 0
2 years ago
Periodic trends.
OLga [1]
11. is most likelyy b
3 0
4 years ago
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lora16 [44]
Which one I'm so confused
3 0
3 years ago
A particular element has the following set of properties:
vaieri [72.5K]

Answer:

A. Iodine

Explanation:

First 2 points describe it's physical properties. Even if we don't remember them, we can easily figure out the answer to be a non-metal. As, non-metals usually have lower bp and mp than metals.

Both Iodine and hydrogen exists as a 2 atom molecule in gas phase.

But only elements of group 17 (halogens) have 7 electrons in their outer shell.

Again, salts are usually ionic compounds, formed by atoms with a greater difference in their electronegativities. Hence, the one that forms bonds with a metal to form a salt readily can be a non- metal.

All these points indicate that the element must be iodine.

8 0
3 years ago
Consider the following equilibrium process at 686°C. CO2(g) + H2(g) equilibrium reaction arrow CO(g) + H2O(g) The equilibrium co
coldgirl [10]

Answer:

a) The value of the K_c is 0.52.

b)Concentration of all species when equilibrium reestablishes:

[CO_2] = 0.4748 M

[H_2] = 0.0198 M

[CO] = 0.0752 M

[H_2O] =0.0652 M

Explanation:

a)  CO_2(g) + H_2(g)\rightleftharpoons CO(g) + H_2O(g)

Equilibrium concentration of species :

[CO] = 0.050 M, [H_2] = 0.045 M, [CO_2] = 0.086 M, and [H_2O] = 0.040 M

The expression of equilibrium constant is given as :

\K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}

=\frac{0.050 M\times 0.040 M}{0.086 M\times 0.045 M}=0.517\approx 0.52 M

b)

CO_2(g) + H_2(g)\rightleftharpoons CO(g) + H_2O(g)

Initially:

0.50 M    0.045 M      0.050 M   0.040 M

At equilibrium ;

(0.50-x) M    (0.045-x) M      (0.050+x) M   (0.040+x) M

K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}

0.52=\frac{(0.050+x) M\times (0.040+x) M}{(0.50-x) M\times (0.045-x) M}

Solving fro x;

x = 0.0252

Concentration of all species when equilibrium reestablishes:

[CO_2] = (0.50-x) M=(0.50-0.0252)M = 0.4748 M

[H_2] = (0.045-x) M= (0.045-0.0252) M=0.0198 M

[CO] = (0.050+x) M=(0.050+0.0252)M = 0.0752 M

[H_2O] = (0.040+x) M=(0.040+0.0252) M=0.0652 M

8 0
4 years ago
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