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IgorC [24]
2 years ago
10

If you had 6 mol of oxygen and 12 mol of mercury, what would be the limiting reactant? show your work

Chemistry
1 answer:
gayaneshka [121]2 years ago
3 0

The limiting reactant between the reaction of 6 moles of oxygen and 12 moles of mercury is mercury (Hg)

<h3>Balanced equation </h3>

4Hg + O₂ —> 2Hg₂O

From the balanced equation above,

4 moles of Hg reacted with 1 mole of O₂

<h3>How to determine the limiting reactant</h3>

From the balanced equation above,

4 moles of Hg reacted with 1 mole of O₂

Therefore,

12 moles of Hg will react with = 12 / 4 = 3 moles of O₂

From the above calculation, we can see that only 3 moles of O₂ out of 6 moles given is required to react completely with 12 moles of Hg.

Thus, Hg is the limiting reactant and O₂ is the excess reactant .

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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Rudiy27

Answer:

1943.1 moles

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 50200 L

Temperature (T) = 25 °C

Pressure (P) = 720 mmHg

Number of mole (n) of H₂ =?

Next, we shall convert 25 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 25 °C

Temperature (T) = 25 °C + 273

Temperature (T) = 298 K

Next, we shall convert 720 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

720 mmHg = 720 mmHg × 1 atm / 760 mmHg

720 mmHg = 0.947 atm

Thus, 720 mmHg is equivalent to 0.947 atm

Finally, we shall determine number of mole of Hydrogen gas, H₂, needed to fill the balloon as follow:

Volume (V) = 50200 L

Temperature (T) = 298 K

Pressure (P) = 0.947 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) of H₂ =?

PV = nRT

0.947 × 50200 = n × 0.0821 × 298

47539.4 = n × 24.4658

Divide both side by 24.4658

n = 47539.4 / 24.4658

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Answer:

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When one atom of carbon reacts with two atoms of oxygen, they combine to form one molecule of carbon dioxide. How many atoms of
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The equation is: C+O2=>CO2

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The answer: there are 20 atoms of oxygen

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