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Lisa [10]
3 years ago
11

Periodic trends.

Chemistry
1 answer:
OLga [1]3 years ago
3 0
11. is most likelyy b
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Formula of a substance in water is followed by what symbol
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The substance is followed by H2O
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Help plz:)))I’ll mark u Brainliest
Triss [41]

Answer:

Explanation:

We want the energy required for the transition:

CO  2 ( s ) + Δ → C O 2 ( g )

Explanation:

We assume that the temperature of the gas and the solid are EQUAL.

And thus we simply have to work out the product:

2 × 10^ 3 ⋅ g × 196.3 ⋅ J ⋅ g − 1  to get an answer in  Joules  as required.

What would be the energy change for the reverse transition:

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2 years ago
What is the Bond Type and Molecular polarity of PCl3?
DedPeter [7]
It is covalent bonding. The electrons are shared between the phosphorus and the chlorines.

covalent bonding is when electrons are shared between two elements.

molecular polarity is a little bit complicated, but I will try to explain ;)
PCl3 is an alternation on tetrahedral molecules.
It means that P has one lone pair of electrons. This pair of electrons are only attracted to the P nuclei and thus a greater freedom of motion.
This means that their orbital is bigger and this pushes the 3 Cl atoms closer together.
The angle between each Cl now is 107 and the angle between Cls and P is greater than 107.
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4 0
3 years ago
Read 2 more answers
.Inherited traits are passed from parent to offspring by information coded in
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Answer:

Inherited traits are passed from parent to offspring by information coded in

the DNA or Deoxyribonucleic Acid

8 0
3 years ago
Q2.  0.254 g of KHP (204 g/mol) titrated against 20.0 mL of unknown NaOH (40.0 g/mol) solution to get the end point of phenolpht
Vera_Pavlovna [14]

Answer:

<u>Mass concentration (g/L) </u><u><em>= 2.49g/L.</em></u>

Explanation:

No. of moles = \frac{mass}{molar mass}

= \frac{0.254}{204} = 0.001245 moles

Concentration of KHP (C1) in litres = n/v

= \frac{0.001245}{0.02} = 0.062 mol/L

We know that:

C_{1} V_{1} = C_{2} V_{2}

where c1v1 and c2v2 are the products of concentration and volumes of KHP and NaOH respectively.

Since mole ratio is 1 : 1.

1 mole of NaOH - 40g

0.001245 mole of NaOH = 40 × 0.001245 = 0.0498g

⇒0.0498g of NaOH was used during the titration

<u><em>∴Mass concentration (g/L) = 0.0498g ÷ 0.02L</em></u>

<u><em>= 2.49g/L.</em></u>

3 0
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