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Lubov Fominskaja [6]
4 years ago
8

What does kevlar mean??

Physics
1 answer:
Anit [1.1K]4 years ago
6 0
A kevlar is a synthetic fiber of high tensile strength used especially as a reinforcing agent in the manufacture of tires and other rubber products, in addition to protective gear. ex ( helmets, vests )
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Any fracture or system of fractures along which Earth moves is known as a
azamat
The answer is B.) Stress 
7 0
3 years ago
Speed is a vector quantity. Do you agree? Justify your answer.
abruzzese [7]

Answer:

<h2>No </h2>

Explanation:

because speed is the rate of change in the distance travelled by an object

so, speed is scalar quantity.

<h2>Mark me as brainlist</h2>
8 0
3 years ago
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on earth a block is placed on a frictionless table. When a 50 North horizontal force is applied to the block, it accelerates at
melamori03 [73]

As per Newton's II law we know that

F = ma

here

F = applied unbalanced force

m = mass of object

a = acceleration of object

now it is given that force F = 50 N North applied on block on earth due to which block will accelerate by 4 m/s^2

so here from above equation

50 = m* 4

m = \frac{50}{4} = 12.5 kg

Now we took another situation where block is placed on surface of moon and again force F = 25 N is applied on the block

So we will again use Newton's II law

F = ma

25 = 12.5 * a

a = \frac{25}{12.5}

a = 2 m/s^2

so block will accelerate on moon by acceleration 2 m/s^2

5 0
3 years ago
What’s the difference between weight and support force? *oof*
grandymaker [24]
Force is a measure of the interaction between bodies, mass is a measure of the amount of material in an object, weight is the gravitational force acting on a body (although for trading purposes it is taken to mean the same as mass) and load usually means the force exerted on a surface or body
4 0
4 years ago
Using the conversion factor from eV (electron volts) to joules, determine which energy line for an electron dropping from one en
Tom [10]

Explanation:

Wavelength in an emission spectrum,  \lambda=435\ nm=435\times 10^{-9}\ m  

The energy of an electron is given by :

E=\dfrac{hc}{\lambda}

Where

h is the Planck's constant

c is the speed of light

For 435 nm, the energy of the electron will be :

E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8\ m/s}{435\times 10^{-9}}

E=4.57\times 10^{-19}\ J

We know that 1\ eV=1.6\times 10^{-19}\ J

So, E=\dfrac{4.57\times 10^{-19}}{1.6\times 10^{-19}}

So, E = 2.86 eV

The energy of the electron dropping from one energy level is 2.86 eV. We know that,

\dfrac{hc}{\lambda}=E_{n_2}-E_{n_1}

From the given energy levels :

E_5-E_2=-0.544-(-3.403)

E_5-E_2=2.859\ eV

So, the transition must be from E₅ to E₂. Hence, this is the required solution.                                             

5 0
4 years ago
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