Answer:
f = 276.6 Hz
Explanation:
This musical instrument can be approximated to a tube system where each tube has one end open and the other closed.
In the closed part there is a node and in the open part a belly or antinode. Therefore the wavelength is
L = λ/ 4
speed is related to wavelength and frequency
v = λ f
λ = v / f
we substitute
L = v / 4f
f = v / 4L
the speed of sound at 20ºC is
v = 343 m / s
let's calculate
f =
f = 276.6 Hz
Answer:
![I = \frac{9.12x10^{-8} C}{0.007 s}= 1.30285 x10^{-5} \frac{C}{s}=1.30285 x10^{-5} A = 13.02 \mu A](https://tex.z-dn.net/?f=%20I%20%3D%20%5Cfrac%7B9.12x10%5E%7B-8%7D%20C%7D%7B0.007%20s%7D%3D%201.30285%20x10%5E%7B-5%7D%20%5Cfrac%7BC%7D%7Bs%7D%3D1.30285%20x10%5E%7B-5%7D%20A%20%3D%2013.02%20%5Cmu%20A)
Explanation:
For this case we have the following info given:
Number of Na+ ions ![5.7 x10^{11} ions](https://tex.z-dn.net/?f=%205.7%20x10%5E%7B11%7D%20ions)
Each ion have a charge of +e and the crage of the electron is ![1.6 x10^{-19}C](https://tex.z-dn.net/?f=%201.6%20x10%5E%7B-19%7DC)
The time is given
if we convert this into seconds we got:
![t = 7ms * \frac{1s}{1000 ms}= 0.007s](https://tex.z-dn.net/?f=%20t%20%3D%207ms%20%2A%20%5Cfrac%7B1s%7D%7B1000%20ms%7D%3D%200.007s)
Now we can use the following formula given from the current passing thourhg a meter of nerve axon given by:
![Q = Ne](https://tex.z-dn.net/?f=%20Q%20%3D%20Ne)
Where N represent the number of ions, e the charge of the electron and Q the total charge
If we replace on this case we have this:
![Q= 5.7x10^{11} * (1.6 x10^{-19}C) = 9.12x10^{-8} C](https://tex.z-dn.net/?f=%20Q%3D%205.7x10%5E%7B11%7D%20%2A%20%281.6%20x10%5E%7B-19%7DC%29%20%3D%209.12x10%5E%7B-8%7D%20C)
And from the general definition of current we know that:
![I =\frac{Q}{t}](https://tex.z-dn.net/?f=%20I%20%3D%5Cfrac%7BQ%7D%7Bt%7D)
And since we know the total charge Q and the time we can replace:
![I = \frac{9.12x10^{-8} C}{0.007 s}= 1.30285 x10^{-5} \frac{C}{s}=1.30285 x10^{-5} A = 13.02 \mu A](https://tex.z-dn.net/?f=%20I%20%3D%20%5Cfrac%7B9.12x10%5E%7B-8%7D%20C%7D%7B0.007%20s%7D%3D%201.30285%20x10%5E%7B-5%7D%20%5Cfrac%7BC%7D%7Bs%7D%3D1.30285%20x10%5E%7B-5%7D%20A%20%3D%2013.02%20%5Cmu%20A)
The current during the inflow charge in the meter axon for this case is ![13.02 \mu A](https://tex.z-dn.net/?f=%2013.02%20%5Cmu%20A)
They are right the answer is A true
Answer: Potassium iodide
Explanation: their you go