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RoseWind [281]
2 years ago
6

identify the action reaction forces in each picture the first picture is done for you write your answer on a separate sheet of p

aper​

Physics
1 answer:
xxMikexx [17]2 years ago
4 0

Newton's Third Law of Motion states that for every action there must exist an equal but opposite reaction.

This ultimately implies that, Newton's Third Law of Motion is a law based on action-reaction force pairs.

In this exercise, you're required to identify the action-reaction forces in the attached picture.

Under condition A, a boy is leaning against a wall;

  • The force being exerted by the boy on the wall is a force of action.
  • The force being exerted by the wall on the boy is a force of reaction.

Under condition B, a boy is jumping off a diving board.

  • The force being exerted by the feet of the boy on the diving board is a force of action.
  • The force being exerted by the diving board on the feet of the boy is a force of reaction.

Under condition C, a nail is being hammered into the wall.

  • The force being exerted by the hammer on the nail is a force of action.
  • The force being exerted by the nail on the hammer is a force of reaction.

Under condition D, a man is walking on a ground (floor).

  • The force being exerted by the foot of the man on the ground (floor) is a force of action.
  • The force being exerted by the ground (floor) on the foot of the man is a force of reaction.

Under condition E, a boy is holding a ball;

  • The force being exerted by the hand of the boy on the ball is a force of action.
  • The force being exerted by the ball on the hand of the boy is a force of reaction.

Read more: brainly.com/question/15170643

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Explanation:

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Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

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where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

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K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

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Answer:

correct answer is b    Z --->Z+1

Explanation:

In the processes of radioactive decay there are three basic processes the emission of alpha particles and the emission of beta rays and the emission of ayos range

The emission of a beta ray implies the transformation of a neutral into a proton, which implies the increase of the atomic number in a unit

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the atomic mass does not change since the mass of the two particles is practically the same, to balance the reaction antineutrino must also be emitted

The daughter particle is in an execrated state and passes to its base state with the emission of a gamma ray that does not change its atomic number or its atomic mass.

Consequently, from the above the correct answer is b

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