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Rus_ich [418]
3 years ago
14

A planet is orbiting its star at a maximum radius of 1.2 x 10^7 meters. If the mass of the star is 2 x 10^30 kg, what is the tim

e period of the orbit?
22.6 seconds


A. 80 seconds


B. 22.6 days



C.80 days


D.22.6 minutes
Physics
1 answer:
kirill115 [55]3 years ago
5 0







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Which processes cause rocks to be exposed<br> at Earth's surface? SC.7..6.2
seropon [69]

Answer:

weathering

Explanation:

5 0
3 years ago
When water freezes, its volume increases by 9.05%. What force per unit area is water capable of exerting on a container when it
AnnZ [28]

Answer:

The Pressure is 0.20 MPa.

(b) is correct option.

Explanation:

Given that,

Change in volume = 9.05%

{tex]\dfrac{\Delta V}{V_{0}}=0.0905[/tex]

We know that.

The bulk modulus for water

B=0.20\times10^{10}\ N/m^2

We need to calculate the pressure difference

Using formula bulk modulus formula

B=\Delta P\dfrac{V_{0}}{\Delta V}

\Delta P=B\dfrac{\Delta V}{V_{0}}

\Delta P=0.2\times10^{10}\times0.0905

\Delta P=0.2\times10^{6}\ Pa

\Delta P=0.20 MPa

Hence, The Pressure is 0.20 MPa.

6 0
4 years ago
A group of stars connected by lines is circled and labeled Saturn.
likoan [24]
Answer: scorpion I think
3 0
2 years ago
How to solve 30(a)<br><br> Give solution asap.
expeople1 [14]

Answer:

They will not meet

h-hX=1.2*g*t²

hX=v0*t-(1/2*g*t²)

Explanation:

fall h=1/2*g*t²

elevation time if v0=20 m/s  te=v0/g=20 m/s /9.81 m/s²=2.0387s

hmax=v0²/(2*g)=(400 m²/s²)/19.62 m/s²2=20.387 m

free fall

t=2.0387s yields hX=1/2*g*t²=20.387 m

h-hX=200m - 20.387 m=179,613 m.

so, the second body has not enough initianoal speed to reach a meeting point

5 0
3 years ago
The velocity time graph of an object is shown below. How far does the object travel in the time interval t =4 s to t = 6 s?
Trava [24]

The distance covered by the object between t =4 s and t = 6 s is 4 m

Explanation:

In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.

Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.

We see that we have to calculate the area of a triangle, with:

Base:

b=6-4 = 2

And height:

h=4-0 = 4

Therefore, the area is

A=\frac{1}{2}bh=\frac{1}{2}(2)(4)=4

So, the distance covered by the object is 4 m.

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

3 0
3 years ago
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