Answer:
the answer for the question is 13°
First, determine the number of computers that are needed for 924 students.
n = (924 students)(5 computers / 12 students)
n = 385 computers
Since, there are only 125 computers, the difference can be calculated.
d = 385 computers - 125 computers
d = 260 computers
Hence, 260 more computers are still needed.
Answer:
Step-by-step explanation:
x decreases w/o bound, so x becomes a very large -ve no.
f(x)=5^(x-1) becomes 5^(large -ve no.) which will be almost zero
x increases w/o bound, so x becomes a very large +ve no.
f(x)=5^(x-1) becomes 5^(large +ve no.) which will keep increasing w/o bound
if u provide wat the choices are from ur Q in comments, i will pick the right one 4 u
Answer:
4y
Step-by-step explanation:
4y is a term in itself 3 and x separate aren't and 4x + 7 is an equation not a term.
From the 64 values in the table on the left, count how many fall within the given ranges under the "classes" column in the table on the right. The "frequency" is the number of values in the data that belong to a given "class".
For example, "< -16.0" means "values below -16.0". Only one number satisfies this: -16.2 (first row, third column). So the frequency for this class is just 1.
Then for the range "-15.9 - 13.0", which probably means "numbers between 15.9 and -13.0, inclusive", the frequency is 0 because every number in the table is larger than the ones in this range.
And so on.
