Answer:
D. 2.5 × 10–4 M
Explanation:
Data given in the question are;
rate constant of 5.0 × 10–2 mol/L·s
[A]0 = 1.0 × 10–3 M
5 × 10–3 sec
It was mentioned that the reaction is a zero order reaction. One interesting charaacteristics about zero order reactio is that the rate of reaction is indepenedent on the concentrations of the reactants.
This means in zero order reactions, we have;
Rate = Rate constant
Rate = 5.0 × 10–2 mol/L·s
What is the concentration of B after 5 × 10–3 sec?
Concentration = Rate * Time
Concentration = 5.0 × 10–2 * 5 × 10–3
Concentration = 2.5 × 10–4 M
Correct option = D
Answer:
See below
Explanation:
The common formula of the same alkene series is CnH2n, where n is the quantity of atoms of carbon. Owing to the hydrocarbons of alkenes with at least one double carbon relation, the alkene-like sequence starts with ethen C2H4.
<em><u>Hope this helps.</u></em>
Answer:
lAs can be seen from the chemical equation, each mole of
F
e
2
C
O
3
needs 3 moles of
C
O
. If 30 moles of
C
O
are used, only 10 moles of
F
e
2
C
O
3
can be reduced, generating 20 moles of
F
e
, corresponding to 1117 grams of iron.
Answer:
0.0063mol
Explanation:
Number of moles (n) in a substance can be calculated by dividing the number of atoms (nA) of that substance by Avagadro's number i.e. 6.02 × 10^23. That is; n = nA ÷ 6.02 × 10^23
1 mol of Gold = 6.02 × 10^23 atoms
Therefore, 3.8 x 10^21 atoms of Gold will be;
3.8 x 10^21 ÷ 6.02 × 10^23
= 3.8 ÷ 6.02 × 10^ (21 - 23)
= 0.6312 × 10^-2
= 0.0063mol of Gold
Answer:
MgCI2+ ___ AgNO3-->___Mg(NO3)2
i think u put 2 before NO3
Explanation: