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san4es73 [151]
3 years ago
12

What is the volume of 3.5 moles of oxygen gas (O2) at standard temperature and pressure (STP)?

Chemistry
1 answer:
baherus [9]3 years ago
4 0
1 mole ----------- 22.4 L ( at STP )
3.5 mols --------- ?

V  = 3.5 x 22.4 / 1

V = 78.4 L

hope this helps!


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Which of the following would not be considered an observation in terms of the scientific method?
prohojiy [21]

Answer:

the first option, tasting a pasta sauce after adding a new ingredient.

Explanation:

tasting a pasta sauce after adding a new ingredient is not an observation because there is no qualitative or quantitative data to be taken from that experience.

4 0
3 years ago
This table has information about the heat of fusion and the heat of vaporization of different substances. A 3-column table with
blagie [28]

H₂S

<h3>Further explanation</h3>

Given

ΔH fusion and ΔH vaporization  of different substances

Required

The substance absorbs 58.16 kJ of energy when 3.11 mol vaporizes

Solution

We can use the formula :

\tt \Delta H=\dfrac{Q}{n}

Q=heat/energy absorbed

n = moles

The heat absorbed : 58.16 kJ

moles = 3.11

so ΔH vaporization :

\tt \Delta H_{vap}=\dfrac{58.16~kJ}{3.11~mol}\\\\\Delta H_{vap}=18.7~kJ/mol

The correct substance which has ΔH vaporization = 18.7 kj / mol is H₂S

(H₂S from the data above has ΔH fusion = 2.37 kj / mol and ΔH vaporization = 18.7 kj / mol)

3 0
3 years ago
Read 2 more answers
.Florida phosphate accounts for ___ of the world's fertilizer supply?Immersive Reader
Stells [14]

Answer: 25%

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4 0
3 years ago
What is the shortest half life
N76 [4]

Answer:

Hey!

Your answer is element A

Explanation:

Using the graph, the element A's emission of radioactive particles ends approximately after 6 years...

A HALF-LIFE IS "HALF" OF THAT TIME PERIOD!

So if the radiation goes for 6 years the half-life is 6 divided by two which gives you 3 years!

The rest however have a longer half-life...

Because they all end at 14 yrs so their half-life in 7 years!

HOPE THIS HELPS!!

8 0
3 years ago
9. Thallium-208 has a half-life of 3.053 min. How long will it take for 120 g of it to decay
damaskus [11]

Answer:

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

Explanation:

Radioactive isotopes decay exponentially in time, the mass of the isotope (m(t)), in grams, is described by the formula in time (t), in minutes:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

m_{o} - Initial mass of the isotope, in grams.

\tau - Time constant, in minutes.

In addition, the time constant associated with the isotope decay can be described in terms of half-life (t_{1/2}), in minutes:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m(t) = 7.5\,g, m_{o} = 120\,g and t_{1/2} = 3.053\,min, then the time taken by the isotope is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{3.053\,min}{\ln 2}

\tau \approx 4.405\,min

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(4.405\,min)\cdot \ln \left(\frac{7.5\,g}{120\,g} \right)

t \approx 12.213\,min

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

4 0
3 years ago
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