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2 years ago

Please help SO CONFUSED

Mathematics

1 answer:

gulaghasi [49]2 years ago

5 0

Answer:

SOH-CAH-TOA

$h = \sqrt{ 9^{2} +5^{2} }$

~~~~~~~~~~

H= $\sqrt{106}$

O= 5

A= 9

~~~~~~~~~~~~~~~~

Sin = $\frac{5}{\sqrt{106 } }$

Cos= $\frac{9}{\sqrt{106 } }$

Tan = $\frac{5}{9 }$

Step-by-step explanation:

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Given :-

Line p has an equation of y = 5/3x - 4 .
Line q includes point (-10,-3) and is perpendicular to the line p .

To Find :-

The equation of line q .

Solution :-

The equation of the line p is ,

$\sf\blue{\longrightarrow}$ y = 5/3x - 4

On comparing to slope intercept form of the line which is y = mx + c , we have ,

$\sf\blue{\longrightarrow}$ m = 5/3

Now as we know that the product of slopes of two perpendicular lines is -1 . So the slope of the perpendicular line will be ,

$\sf\blue{\longrightarrow} m_{\perp} = -3/5$

Now here the line q passes through the point (-10,-3) . So on using the point slope form of the line we get ,

$\sf\blue{\longrightarrow} y - y_1 = m(x-x_1)$

$\sf\blue{\longrightarrow}$ y - (-3) = -3/5[ x-(-10)]

$\sf\blue{\longrightarrow}$ y +3 = -3/5(x+10)

$\sf\blue{\longrightarrow}$ y+3 = -3/5x - 6

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Hence the required answer is y = -3/5x - 9 .

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2 years ago

Read 2 more answers

The slope of the line whose equation is x + y = 6 is a. -1 b. 1 c. 6

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Let's rearrange the equation x + y = 6 to slope-intercept form. Solve for y.

x + y = 6

To get the y variable on the left-hand side alone, subtract x from each side.

x + y - x = 6 - x
y = 6 - x

Rearrange the right-hand side.

y = -x + 6

Now we have it in the slope-intercept form. And to find the slope, we look at the coefficient of x. But there is no coefficient of the -x term!

In all reality, there is. However, it's just 1. -1x is the same thing as -x. We don't show the 1 because it has no effect.

So, -1 is the slope.

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