Heya!
Question #15:
To find the perimeter of the object, you can count the amount of squares that are on the outside of the object. After you country all around the object, the perimeters is 22 units (Option D)
Question #16:
Since we know the total perimeter, we can divide by the amount of sides a hexagon has because all of the sides are the same length. A hexagon has 6 sides. 42 / 6 = 7 inches (Option A)
Question #17:
To calculate the perimeter of the rectangle, you can add all the sides together. First, find common denominators.
6 1/2 = 6 2/4 and 3 1/4
Now, add all the sides together.
6 2/4 + 6 2/4 + 3 1/4 + 3 1/4 = 19 1/2 cm (Option B)
Question #18:
We can find the perimeter of the semi circle and square separately. Only take the perimeter of the square using 3 sides since the fourth sides is in the semi circle.
8 + 8 + 8 = 24 inches
Circumference of a semi circle formula: C = πd
C = (3.14)(8)
C = 25.12
Now, add both perimeters together.
24 + 25.12 = 49.12 inches (Option D)
Best of Luck!
Answer:
Company A:
c = 40 + 2s
Company B:
c = 20 + 4s
Equal costs => 40 + 2s = 20 +4s => 4s - 2s = 40 - 20 => 2s = 20 => s = 20/2
=> s = 10
And c = 20 + 4s = 20 + 4(10) = 20 + 40 = 60
Step-by-step explanation:
duh obviously the answer is idk, and let me tell you why
Step-by-step explanation:
because when you add 2+4 and then it gives you 78 now you can square root that 78 and it will give you 8 and after that you get 8 of your fingers and play with yourself a little bit but not too much, therefore the answer is idk.
hope i was helpful
Answer:
24
Step-by-step explanation:
Factorial is applicable only for natural numbers and 0.
0! =1 trivially.
FOr other numbers, factorial is defined as 1x2x...n
For example 1! = 1
2! = 1x2 = 2
and so on.
i.e. n! = product of all natural numbers from 1 to n
= 1x2x....n
Using the above
we have n =4
Natural numbers from 1 to 4 are 1,2,3,4
Find the product of these 4 natural numbers to get 4!
4! = 1x2x3x4 = 24
Answer:
The student is wrong because the sum of any two sides of a triangle should be greter than the third side. The length of a single side of a triangle can not be half or more than half of the perimeter of that triangle. And since the given length is more than half of the perimeter , the student is incorrect .
