The car covers a distance <em>d</em> after time <em>t</em> of
<em>d</em> = (2.8 m/s²) <em>t</em>²
Solve for <em>t</em> when <em>d</em> = 69 m:
69 m = (2.8 m/s²) <em>t</em>²
<em>t</em>² = (69 m) / (2.8 m/s²)
<em>t</em> ≈ 4.96 s
v1f = -0.16 ms
Explanation:
Use the conservation law of linear momentum:
m1v1i + m2v2i = m1v1f + m2v2f
where
v1i = v2i = 0
m1 = 160 kg
m2 = 0.50 kg
v2f = 50m/s
v1f = ?
So we have
0 = (160 kg)v1f + (0.5 kg)(50 m/s)
v1f = -(25 kg-m/s)/(160 kg)
= -0.16 m/s
Note: the negative sign means that its direction is opposite that of the arrow.
I’m guessing is because she uses force to throw the ball, allowing the energy to move the person.
sorry if it’s not 100% correct
Given data
*The mass of Bruce is m_1 = 45 kg
*The initial velocity of the Bruce is u_1 = 2 m/s
*The mass of the biff is m_2 = 90 kg
*The initial velocity of the Biff is u_2 = -7 m/s
*The final velocity of the first glider is v_2 = -1 m/s
According to the law of conservation of linear momentum, the total linear momentum of a system remains constant
Applying the law of conservation of momentum as
Substitute the known values in the above expression as
Hence, the speed of the bruce knock backwards is v_1 = -10 m/s
Answer:
are you asking how the planets are arranged
