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kirill115 [55]
3 years ago
13

Venus has about the same mass as Earth and is about the same distance from the Sun. Yet Venus does not support life. An importan

t difference between Earth and Venus is that Venus lacks A) an atmosphere. B) gravity and water. C) a similar chemical composition. D) water and moderate temperatures.
Physics
2 answers:
Bogdan [553]3 years ago
8 0
The correct answer is: (A) An Atmosphere

Explanation:
The atmosphere of Venus is almost ninety times denser than that of Earth. Due to Venus' denser atmosphere and chemical composition (as its atmosphere comprises of over 96% of Carbon dioxide), it experience an immense greenhouse effect. That is why its surface temperature remains higher than 470°. At that very high temperature, it is impossible to have life on the surface of Venus.
MAXImum [283]3 years ago
3 0

Answer: its D

Explanation:

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An airplane is flying at 635 km per hour at an altitude of 35,000 m. What is its velocity?
Elden [556K]

Distance 350 Km

Time 1 hour

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350Km/h

your answer is a

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3 years ago
I beg you plz help me asap!!!
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Answer:

a.

Explanation:

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When a honeybee flies through the air, it develops a charge of +20 pC . Part A How many electrons did it lose in the process of
Yuri [45]

Answer:

1.3 × 10⁸ e⁻

Explanation:

When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:

20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻

1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:

2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻

7 0
3 years ago
which of the following cannot be increased by using a machine of some kind? work, force, speed, torque
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Explanation:

Work cannot be increased by using a machine of some kind.

8 0
3 years ago
An 7.5 × binocular has 3.7-cm-focal-length eyepieces. What is the focal length of the objective lenses? Express your answer to t
elixir [45]

To solve this problem we will apply the concept of magnification, which is given as the relationship between the focal length of the eyepieces and the focal length of the objective. This relationship can be expressed mathematically as,

\mu = \frac{f_0}{f_e}

Here,

\mu = Magnification

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f_0 = Focal length of the Objective

Rearranging to find the focal length of the objective

f_0 = \mu f_e

Replacing with our values

f_0 = 7.5* 3.7cm

f_0 = 27.75cm

Therefore the focal length of th eobjective lenses is 27.75cm

5 0
3 years ago
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