-3(5 + 8x) - 20 ≤ -11 |use distributive property: a(b + c) = ab + ac
-15 - 24x - 20 ≤ -11
-35 - 24x ≤ -11 |add 35 to both sides
-24x ≤ 24 |change signs
24x ≥ -24 |divide both sides by 24
x ≥ -1
Answer:
B
Step-by-step explanation:
If you arrange a statistics in order from least to greatest, the middle number is the median.
If there is even number of numbers in a list, let it be n numbers, then we take the average of n/2th and n/2 + 1 th terms.
Here, all of them have 6 numbers, so 6/2 = 3 and 4th, we take average of 3rd and 4th number to find the median.
Since they are arrange in order we check each:
Jon = average of 6 and 7, (6+7)/2 = 6.5
Leroy = average of 6 and 8, (6+8)/2 = 7
Simon = average of 5 and 6, (5+6)/2 = 5.5
Leroy's median is the greatest (7).
I'm not sure what this question means exactly, maybe the principals goal is unrealistic?
1 and 2 i can't answer without proper data.
3. x+2x+2x+6 = 86
5x+6 = 86
-6 -6
5x = 80
x = 16
Side one: x is 16
Side two: 2x is 2(16) = 32
Side three: 2x+6 is 38
Answer:
12 mph
Step-by-step explanation:
The relationship between jogging speed and walking speed means the time it takes to walk 4 miles is the same as the time it takes to jog 8 miles. Then the total travel time (0.75 h) is the time it would take to jog 1+8 = 9 miles. The jogging speed is ...
(9 mi)(.75 h) = 12 mi/h . . . average jogging speed
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<em>Check</em>
1 mile will take (1 mi)/(12 mi/h) = 1/12 h to jog.
4 miles will take (4 mi)/(6 mi/h) = 4/6 = 8/12 h to walk.
The total travel time is (1/12 +8/12) h = 9/12 h = 3/4 h. (answer checks OK)
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<em>Comment on the problem</em>
Olympic race-walking speed is on the order of 7.7 mi/h, so John's walking speed of 6 mi/h should be considered quite a bit faster than normal. The fastest marathon ever run is on the order of a bit more than 12 mi/h, so John's jogging speed is also quite a bit faster than normal. No wonder he got tired.
