2 years ago

Which of the following is the range of the function based on the input-output

Mathematics

1 answer:

N76 [4]2 years ago

8 0

Answer:

5, 100, 10, 105, 15, 110,20}

Step-by-step explanation:

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2 years ago

What is the image point of (8, 4) after a translation left 2 units and down 4 units?

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Answer:

(6, 0 )

Step-by-step explanation:

A translation to the left means subtract 2 from the x- coordinate

A translation down means subtract 4 from the y- coordinate

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3 years ago

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2 years ago

Solve the differential equation. y' + 5xey = 0.

Gwar [14]

Answer:

The solution is $y = - ln(\frac{5}{2}x^{2} + C)$

Step-by-step explanation:

To solve the differential equation, we will find $y$

From the given equation, y' + 5xey = 0.

That is, $y' + 5xe^{y} = 0$

This can be written as

$\frac{dy}{dx} + 5xe^{y} = 0$

Then,

$\frac{dy}{dx} = - 5xe^{y}$

$\frac{dy}{e^{y}} = - 5x dx$

Then, we integrate both sides

$\int {\frac{dy}{e^{y}}} =\int {- 5x dx}$

$\int {e^{-y}dy }} =\int {- 5x dx}$

Then,

$-e^{-y} = -\frac{5}{2}x^{2} + C$

$e^{-y} = \frac{5}{2}x^{2} + C$

Then,

$ln(e^{-y}) = ln(\frac{5}{2}x^{2} + C)$

Then,

$-y = ln(\frac{5}{2}x^{2} + C)$

Hence,

$y = - ln(\frac{5}{2}x^{2} + C)$

8 0

3 years ago