It is a scaler because it’s only fully describes by a magnitude and a numerical alone
Answer:
76.73 ft/s
Explanation:
Let the final velocity is v.
initial velocity, u = 96 ft/s
g = 32 ft/s²
height, h = 52 feet
use third equation of motion
v² = u² - 2 gh
v² = 96 x 96 - 2 x 32 x 52
v = 76.73 ft/s
Thus, the speed of the ball as it reaches the ground is 76.73 ft/s.
KE = PE
1/2 m • v^2 = mgh
1/2 • v^2 = gh
V^2/2 = gh
2 • (v^2/2) = 2 • (gh)
V^2 = 2gh
V = sq root (2gh).
Answer:
The critical radius of the plastic insulation is 0.72 inches.
Explanation:
Given that,
Diameter = 0.091 in
Thickness = 0.02 in
Initial temperature = 90°F
Final temperature = 50°F
Heat transfer coefficient = 2.5 Btu/h.ft²°F
Material conductivity = 0.075 Btu/h.ft °F
We need to calculate the critical radius of the plastic insulation
Using formula of critical radius

Where, k = Material conductivity
h = Heat transfer coefficient
Put the value into the formula



Hence, The critical radius of the plastic insulation is 0.72 inches.