"Mars" like earth experiences seasons
In short, Your Answer would be option A
Hope this helps!
Answer:
Explanation:
The time at which an object from from rest depends on air resistance, the height, gravity.
Since the question says we should neglect air resistance and both the ball and the bullet are from the same height they will get to the ground and the same time since they are both fired on earth which has the same gravity..
H=ut+1/2gt^2.
For an object dropping from a height the initial velocity is zero, therefore u=0m/s.
The formula becomes
t=√(2H/g)
So the time and object get to the ground depends on the height from the ground and gravity...
So since no air resistance they will get to the ground together.
The product of (wavelength) x (frequency) is always the same number ... the wave's speed.
So if the wavelength is somehow reduced to 1/4 its original length, the <em>frequency is immediately multiplied by 4</em> . That's the only way their product can remain the same.
Answer:
1. 18.25 m/s
2. 0 m/s
Explanation:
1.So the centripetal acceleration of the ball at this lowest point must be, taking gravity into account
The speed at this point would then be
2. Similarly, if T = mg, then the centripetal acceleration must be
As the ball has no centripetal acceleration, its speed must also be 0 as well.
Cars 'A' and 'C' look like they're moving at the same speed. If their tracks are parallel, then they're also moving with the same velocity.
