The question is incomplete. Here is the complete question:
A whale swims due east for a distance of 6.9 km, turns around and goes due west for 1.8 km and finally turns around again and heads 3.7 km due east. (a) What is the total distance traveled by the whale? (b) What are the magnitude and direction of the displacement of the whale?
Answer:
(a) Distance = 12.4 km
(b) Displacement = 8.8 km due east
Explanation:
Consider east direction as positive and west direction as negative.
Given:
The motion is along the east-west line.
The whale first swims 6.9 km due east, then 1.8 km due west and again 3.7 km due east.
(a)
Distance traveled by the whale is equal to the sum of the lengths of all the distances traveled. Therefore,
Distance traveled = 6.9 km + 1.8 km + 3.7 km = 12.4 km
Therefore, the distance traveled by the whale is 12.4 km.
(b)
Displacement of the whale is given by considering the sign of each of the individual displacements. Therefore,
Displacement of the whale = (+6.9 km) + (-1.8 km) + (+3.7 km)
Displacement of the whale = 6.9 km - 1.8 km + 3.7 km = 8.8 km
The answer is positive. So, the direction is due east.
Therefore, the displacement of the whale is <u>8.8 km due east.</u>