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Bogdan [553]
3 years ago
13

Please help!! Subtract. (x^2+43x+10)−(−10x^2−5x+10) Express the answer in standard form.

Mathematics
2 answers:
Olegator [25]3 years ago
7 0
Answer: 11x^2+48x

---------------------------------------

Work Shown:

(x^2+43x+10) - (-10x^2-5x+10)
x^2+43x+10 - (-10x^2) -(-5x) -(10)
x^2+43x+10 + 10x^2+5x-10
(x^2+10x^2)+(43x+5x)+(10-10)
11x^2+48x+0
11x^2+48x

Oliga [24]3 years ago
4 0

Answer:

11x^2 + 48x

Step-by-step explanation:

Above answer is right, took the test.

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n+1

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Find the value of x and y​
DerKrebs [107]

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It's hard to make out which is x and y, if x is lower right and y is at the top, then:

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4 0
3 years ago
A rectangular garden must have a perimeter of 155 feet and an area of at least 1400 square feet. Describe the possible lengths o
snow_lady [41]

Answer:

Step-by-step explanation:

Perimeter of a garden =  2(L+W)

Area of the gerden = LW

L is the length

W is the width

Given

Perimeter = 155ft

Area = 1400ft²

Substitute

1400 = LW

155 = 2L+2W

from 1;

W = 1400/L

Substitute into 2;

155 = 2L + 2(1400/L)

155 = 2L + 2800/L

155L = 2L² + 2800

2L²-155L + 2800 = 0

Factorize

L = 155±√155²-4(2)(2800)/4

L = 155±√24025-22400/4

L = 155±√1625/4

L = L = 155±40.31/4

L = 194.31/4

L = 48.82 feet and;

L = 155-40.31/4

L = 28.67ft

Hence the approximate length of the garden is at least 28.67 feet and at most 48.82 feet.

6 0
3 years ago
May someone explain this?Thanks❤
Georgia [21]
2=10/10 so 10/10-3/5=10/10-6/10=4/10 or 2/5
4 0
3 years ago
Read 2 more answers
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