Answer:
λ = 2 m
f = 100 Hz
Explanation:
When struck in the middle an anti-node is formed at the center, So you can derive,
f = frequency of the fundamental mode in producing standing waves
l = resonating length
T = tension of the wire
m = linear density of the wire
(check the attachment)
By substituting,
f = 100 Hz
Wavelength is twice the vibrating length, its in the section standing waves and using that only the equation is derived.
Imagine what happens when two identical waves in opposite direction superimpose. There will be 3 nodes and two anti-nodes where the distance between two nodes is half the wavelength.
The same case happen here, the transverse sound wave traveling along the wire get reflected by a bridge and bounce back on itself where superposition takes place. So two nodes are at the bridges hence the twice of the distance between bridges is the wavelength of the sound wave.
To solve this problem with have to follow the order of operations. (PEMDAS) Parenthesis, Exponents, Multiply, Divide, Add, Subtract.
We'll start with the first set of parenthesis.
(6.02*10^23)
10^23 = 1e+23 (1 followed by 23 zeroes)
6.02*1e+23 = 6.02
Now we'll solve the second set of parenthesis.
(8.65*10^4)
10^4 = 10,000
8.65 * 10,000 = 86,500
Now onto the final step. We multiply together both numbers.
6.02 * 86,500 = 520,730<span>
</span>
<h2>
Hello!</h2>
The answer is:
The voltage of the source is 8.40 Volts.
<h2>
Why?</h2>
To solve the problem, we need to use the Ohm's Law equation base formula.
We have that we can calculate the voltage using the following equation:
So, from the statement we know that:
Now, substituting and calculating we have:
Hence, we have that the voltage of the source is 8.40 Volts.
Have a nice day!
Answer: The reference frame of a passenger in a seat near the center of the train
Explanation:
the speed of light is the same for the passenger and the bicyclist
then the avents are simultaneous fo the passenger not for the bicyclist
the delay between the two events for the bicyclist is
Δt=Δd/vs
where
Δd= lenght of train
vs=speed of sound
the reference frame of a passenger in a seat near the center of the train
Solution:
The space and time transformations are:
x' = γ(x - vt)
t' = γ(t - vx/c²).
In the primed frame the two events are simultaneous, so that Δt' = 0. Also here Δx' = 30. In the unprimed frame Δx' = 30 = γ(Δx - v Δt).......(*)
We also have Δt' = 0 = γ(Δt - vΔx/c²)→Δx = c²Δt/v......(**)
Substituting (**) in (*): 30 = γ(c²Δt/v - vΔt))→Δt = 30/(c²/v - v) =
30/(2c - 0.5c) = 6.7 x 10^(-8)s
