For counting x you use simple equation for the distance covered by the object when it moves with constant velocity:

that gives you 20m after 1st second, 40 m after 2nd second, 60 m after 3rd second and so on.
For counting y you have to use the equation for the distanced covered by the object moving with constantly accelerating velocity (symbols refering to vertical movement):

that gives you 5m after 1st second, 20m afters 2nd second, 45m after 3rd second and so on.
Add minus signs before y positions to receive graph presenting the movement of the ball.
So the points are: P1=[20,-5], P2=[40,-20], P3=[60,-45] and so on... Pn=[x,y].
Answer: 3.9 MW
Explanation:
1 W = 1 J/s
260000 J/s (15 s) = 3,900,000 = 3.9 MW
I would say Anthony has more power than Angel. If they are both exerting the same force on the box, which isnt really mentioned here, which is why I believe this is a bit vague, then the both do the same work. So, if the work is equal then the person with the lower time period would have more power. Since Anthony only took 38 seconds, compared to Angel's 42 I would say that Anthony has more power than Angel.
Answer:
Cannonball b spends more time in the air than cannonball a.
Explanation:
Starting with the definition of acceleration, we have that:

Since both cannonballs will stop in their maximum height, their final velocity is zero. And since the acceleration in the y-axis is g, we have:

Now, this time interval is from the moment the cannonballs are launched to the moment of their maximum height, exactly the half of their time in the air. So their flying time t_f is (the minus sign is ignored since we are interested in the magnitudes only):

Then, we can see that the time the cannonballs spend in the air is proportional to the vertical component of the initial velocity. And we know that:

Finally, since
and
, we can conclude that:

In words, the cannonball b spends more time in the air than cannonball a.