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Oksana_A [137]
4 years ago
13

A bowl contains 4 red balls and 2 green balls. Two balls are selected simultanesouly and at random. What is the conditional prob

abiltiy that both balls are red given that at least one of the selected balls is red?
Physics
1 answer:
AlladinOne [14]4 years ago
7 0

Answer:0.6

Explanation:

Given

Bowl contains 4 red and 2 Green balls

Probability of selecting two red balls given atleast one of the ball is red + Probability of selecting two red balls given that no ball is red =1

Probability of selecting two red balls given that no ball is red =\frac{Probability \ of\ selecting\ two\ red\ balls\ out\ of\ 4\ balls}{probability\ of\ selecting\ 2\ balls\ out\ of\ 6 balls}

P=\frac{^{4}C_2}{^{6}C_2}

P=\frac{2}{5}

Required Probability=1-\frac{2}{5}=\frac{3}{5}

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A bowling ball rolls off the edge of a cliff, moving horizontally at 20 m/s. I have to plot the position of the bowling ball on
liubo4ka [24]
For counting x you use simple equation for the distance covered by the object when it moves with constant velocity:
s=v*t
that gives you 20m after 1st second, 40 m after 2nd second, 60 m after 3rd second and so on.

For counting y you have to use the equation for the distanced covered by the object moving with constantly accelerating velocity (symbols refering to vertical movement):
h=g\frac{t^{2}}{2}
that gives you 5m after 1st second, 20m afters 2nd second, 45m after 3rd second and so on.
Add minus signs before y positions to receive graph presenting the movement of the ball.
So the points are: P1=[20,-5], P2=[40,-20], P3=[60,-45] and so on... Pn=[x,y].
8 0
3 years ago
If a car used 260,000 W of power to complete a race in 15 s, how much work did the car do?
suter [353]

Answer: 3.9 MW

Explanation:

1 W = 1 J/s

260000 J/s (15 s) = 3,900,000 = 3.9 MW

3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
cluponka [151]

I would say Anthony has more power than Angel. If they are both exerting the same force on the box, which isnt really mentioned here, which is why I believe this is a bit vague, then the both do the same work. So, if the work is equal then the person with the lower time period would have more power. Since Anthony only took 38 seconds, compared to Angel's 42 I would say that Anthony has more power than Angel.

6 0
3 years ago
Read 2 more answers
What is the momentum of an 18-kg object moving at 0.5 m/s?
Arada [10]

Answer:

9kgm per second

Explanation:

3 0
2 years ago
Read 2 more answers
Cannonball a is launched across level ground with speed v₀ at an angle of 45. Cannonball b is launched from the same location wi
postnew [5]

Answer:

Cannonball b spends more time in the air than cannonball a.

Explanation:

Starting with the definition of acceleration, we have that:

a=\frac{\Delta v}{\Delta t}\\\\\Delta t= \frac{\Delta v}{a}

Since both cannonballs will stop in their maximum height, their final velocity is zero. And since the acceleration in the y-axis is g, we have:

\Delta t= -\frac{v_{oy}}{g}

Now, this time interval is from the moment the cannonballs are launched to the moment of their maximum height, exactly the half of their time in the air. So their flying time t_f is (the minus sign is ignored since we are interested in the magnitudes only):

t_f=2\frac{v_{oy}}{g}

Then, we can see that the time the cannonballs spend in the air is proportional to the vertical component of the initial velocity. And we know that:

v_{oy}=v_o\sin\theta\\\\\implies t_f=2\frac{v_o\sin\theta}{g}

Finally, since \sin60\°=\frac{\sqrt{3} }{2} and \sin45\°=\frac{\sqrt{2} }{2}, we can conclude that:

t_{fa}=\sqrt{2}\frac{v_o }{g} \\\\t_{fb}=\sqrt{3}\frac{v_o }{g}\\\\\implies t_{fb}>t_{fa}

In words, the cannonball b spends more time in the air than cannonball a.

5 0
3 years ago
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