Question

A bowl contains 4 red balls and 2 green balls. Two balls are selected simultanesouly and at random. What is the conditional probabiltiy that both balls are red given that at least one of the selected balls is red?

Answer 1

Answer:0.6

Explanation:

Given

Bowl contains 4 red and 2 Green balls

Probability of selecting two red balls given atleast one of the ball is red + Probability of selecting two red balls given that no ball is red =1

Probability of selecting two red balls given that no ball is red $=\frac{Probability \ of\ selecting\ two\ red\ balls\ out\ of\ 4\ balls}{probability\ of\ selecting\ 2\ balls\ out\ of\ 6 balls}$

$P=\frac{^{4}C_2}{^{6}C_2}$

$P=\frac{2}{5}$

Required Probability$=1-\frac{2}{5}=\frac{3}{5}$