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8090 [49]
3 years ago
9

Science quiz question #9

Chemistry
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer: I would say its either exit door or the last one.

Explanation: Hope this helps plz mark brainliest.

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2.38 to the nearest hundred
puteri [66]

Answer:

heyooooooooooooo!!

2.00

hope this helps >3

Explanation:

3 0
3 years ago
Read 2 more answers
Which antibody does the body release when it identifies a bacterium or virus?
dlinn [17]

Explanation:

Immunoglobulin M is the first antibody produced on initial exposure to an antigen. It is also known as IgM.

It occurs as a primary response to the antigens against a particular baterium or virus. It is pentavalent in nature and has ten binding sites for antigens.

Therefore, it is concluded that when the body identifies a bacterium or a virus, it releases the antibody IgM.

6 0
3 years ago
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A 100.0-mL sample of 1.00 M NaOH is mixed with 50.0 mL of 1.00 M H2SO4 in a large Styrofoam coffee cup calorimeter fitted with a
worty [1.4K]

Answer:

THE ENTHALPY CHANGE IN KJ/MOLE IS +114 KJ/MOLE.

Explanation:

Heat = mass * specific heat capacity * temperature rise

Total volume = 100 + 50 = 150 mL

Total mass = density * volume

Total mass = 1 * 150 mL = 150 g

So therefore, the heat evolved during the reaction is:

Heat = 150 * 4.18 * ( 31.4 - 22.3)

Heat = 150 * 4.18 * 9.1

Heat = 5705.7 J

Equation for the reaction:

2 NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + 2 H2O(l)  

From the equation, 2 moles of NaOH reacts with 1 mole of H2SO4 to produce 1 mole of Na2SO4 and 2 moles of water

50 mL of 1 M of H2SO4 contains

50 * 1 / 1000 mole of acid

= 0.05 mole of acid

The production of 1 mole of water evolved 5705.7 J of heat and hence the enthalpy changein kJ per mole will be:

0.05 mole of H2SO4 produces 5705.7 J of heat

1 mole of H2SO4 will produce 5705.7 / 0.05 J

= 114,114 J / mole

In kj/mole = 114 kJ/mole.

Hence, the enthalpy change of the reaction in kJ /mole is +114 kJ/mole.

5 0
3 years ago
For many years chloroform (CHCl3) was used as an inhalation anesthetic in spite of the fact that it is also a toxic substance th
Debora [2.8K]

Hey there!:

Molar mass:

CHCl3 = ( 12.01 * 1 )+ (1.008 * 1 ) + ( 35.45 * 3 ) => 119.37 g/mol

C% =  ( atomic mass C / molar mass CHCl3 ) * 100

For C :

C % =  (12.01 / 119.37 ) * 100

C% = ( 0.1006 * 100 )

C% =  10.06 %

For H :

H% = ( atomic mass H / molar mass CHCl3 ) * 100

H% = ( 1.008 / 119.37 ) * 100

H% = 0.008444 * 100

H% = 0.8444 %

For Cl :

Cl % ( molar mass Cl3 / molar mass CHCl3 ):

Cl% =  ( 3 * 35.45 / 119.37 ) * 100

Cl% =  ( 106.35 / 119.37 ) * 100

Cl% = 0.8909 * 100

Cl% = 89.9%


Hope that helps!

4 0
3 years ago
Explain how did you find the qostion
Alekssandra [29.7K]
What do you mean by this?
6 0
2 years ago
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