The equation that is a decomposition reaction is
PbCO3(s) ---> PbO(s) + CO2(g)
That is option D.
<h3>Properties of a decomposition reaction</h3>
A chemical reaction is defined as the combination of substances called reactants to form a product. The various types of chemical reaction include:
- single or double replacement reaction
Decomposition reaction is that type of chemical reaction in which the reactant breaks down to form two or more products.
Therefore the heating of lead (II) carbonate is a decomposition reaction.
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<span>To find the mass of 3.00 moles of magnesium chloride (MgCl2), first record the atomic mass of magnesium (Mg) and chloride (Cl), which are both listed on the periodic table as follows:
Mg=24 g/mole
Cl=38 g/mole
Now, double the Cl mass since there are 2 Cl moles in MgCl2 and then add it to the Mg mass like so:
(38 g/mole*2 moles)+24 g/mole=100 g/mole
Finally, to calculate the mass of 3.00 moles of MgCl2, convert the combined atomic mass to grams as follows:
3.00 moles * 100 g/mole = 300 g</span>
A. Decomposing water requires a high activation energy.
Explanation:
In decomposing water to release hydrogen gas to make fuel cells, the process requires a very high activation energy.
2H₂O ⇆ 2H₂ + O₂
This is the overall reaction. O-H must be broken to release free hydrogen to produce hydrogen gas.
The O-H bond is a very strong force of attraction that requires a high activation energy to overcome.
- The activation energy is the energy barrier that must be overcome before a reaction takes place.
- The sun is a renewable source of energy.
- Water decomposition produces useful oxygen gas needed by all life for cellular respiration.
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Explanation:
Formula to calculate osmotic pressure is as follows.
Osmotic pressure = concentration × gas constant × temperature( in K)
Temperature = 
= (25 + 273) K
= 298.15 K
Osmotic pressure = 531 mm Hg or 0.698 atm (as 1 mm Hg = 0.00131)
Putting the given values into the above formula as follows.
0.698 = 
C = 0.0285
This also means that,
= 0.0285
So, moles = 0.0285 × volume (in L)
= 0.0285 × 0.100
= 
Now, let us assume that mass of 
= x grams
And, mass of 
= (1.00 - x)
So, moles of 
= 
Now, moles of 
= 
= 
= x = 0.346
Therefore, we can conclude that amount of present is 0.346 g and amount of 
present is (1 - 0.346) g = 0.654 g.
The reaction will generally form more reactants than products.
