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Igoryamba
2 years ago
13

The liquid iodomethane has a density of 2.28 g/mL at 20.0°C. If a 109 gram sample of this compound is needed, what volume of the

liquid at 20.0°C must be provided?
Chemistry
1 answer:
stepladder [879]2 years ago
6 0

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Which is the following is a decomposition reaction
lora16 [44]

The equation that is a decomposition reaction is

PbCO3(s) ---> PbO(s) + CO2(g)

That is option D.

<h3>Properties of a decomposition reaction</h3>

A chemical reaction is defined as the combination of substances called reactants to form a product. The various types of chemical reaction include:

  • synthesis reaction

  • combustion reaction

  • decomposition reaction

  • single or double replacement reaction

Decomposition reaction is that type of chemical reaction in which the reactant breaks down to form two or more products.

Therefore the heating of lead (II) carbonate is a decomposition reaction.

Learn more about decomposition reaction here:

brainly.com/question/15229375

5 0
2 years ago
What is the mass of 3.00 moles of magnesium chloride, MgCl2? Express your answer with the appropriate units.
xenn [34]
<span>To find the mass of 3.00 moles of magnesium chloride (MgCl2), first record the atomic mass of magnesium (Mg) and chloride (Cl), which are both listed on the periodic table as follows: Mg=24 g/mole Cl=38 g/mole Now, double the Cl mass since there are 2 Cl moles in MgCl2 and then add it to the Mg mass like so: (38 g/mole*2 moles)+24 g/mole=100 g/mole Finally, to calculate the mass of 3.00 moles of MgCl2, convert the combined atomic mass to grams as follows: 3.00 moles * 100 g/mole = 300 g</span>
5 0
3 years ago
Some fuel cells are powered by hydrogen. Scientists are looking into the decomposition of water (H2O) to make hydrogen fuel with
skad [1K]

A.  Decomposing water requires a high activation energy.

Explanation:

In decomposing water to release hydrogen gas to make fuel cells, the process requires a very high activation energy.

                             2H₂O ⇆ 2H₂  + O₂

 This is the overall reaction. O-H must be broken to release free hydrogen to produce hydrogen gas.

The O-H bond is a very strong force of attraction that requires a high activation energy to overcome.

  • The activation energy is the energy barrier that must be overcome before a reaction takes place.
  • The sun is a renewable source of energy.
  • Water decomposition produces useful oxygen gas needed by all life for cellular respiration.

Learn more:

Source of energy brainly.com/question/2948717

#learnwithBrainly

4 0
3 years ago
"To determine the amount of heroin in the mixture, you dissolve 1.00 g of the white powdery mixture in water in a 100.0-mL volum
UkoKoshka [18]

Explanation:

Formula to calculate osmotic pressure is as follows.

 Osmotic pressure = concentration × gas constant × temperature( in K)

Temperature = 25^{o} C

                      = (25 + 273) K

                      = 298.15 K  

Osmotic pressure = 531 mm Hg or 0.698 atm     (as 1 mm Hg = 0.00131)

Putting the given values into the above formula as follows.

       0.698 = C \times 0.082 \times 298.15 K&#10;

               C = 0.0285

This also means that,

  \frac{\text{moles}}{\text{volume (in L)}} = 0.0285

So,     moles = 0.0285 × volume (in L)

                      = 0.0285 × 0.100

                     = 2.85 \times 10^{-3&#10;}

Now, let us assume that mass of C_{12}H_{23}O_{5}N = x grams

And, mass of C_{12}H{22}O_{11} = (1.00 - x)

So, moles of C_{12}H_{23}O_{5}N = \frac{mass}{\text{molar mass}}

                              = \frac{x}{369}

Now, moles of C_{12}H_{22}O_{11} = \frac{(1.00 - x)}{342}

                   = \frac{x}{369} + \frac{(1.00 - x)}{342}

                  = 2.85 \times 10^{-3}

             = x = 0.346

Therefore, we can conclude that amount of C_{12}H_{23}O_{5}N present is 0.346 g  and amount of C_{12}H_{22}O_{11} present is (1 - 0.346) g = 0.654 g.

4 0
3 years ago
What may be expected when K &lt; 1.0?
Romashka [77]
The reaction will generally form more reactants than products.
8 0
3 years ago
Read 2 more answers
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