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1 year ago

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The liquid iodomethane has a density of 2.28 g/mL at 20.0°C. If a 109 gram sample of this compound is needed, what volume of the

liquid at 20.0°C must be provided?

1 answer:

stepladder [879]1 year ago

6 0

FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF

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a glass of ice at 0 degrees Celsius changes to a glass of water at 0 degrees Celsius what caused the ice to change to water

Tanya [424]

Thermal energy was absorbed.

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3 years ago

Jonathan claims that since only humans can read, it must be an inherited trait, passed from human parents to their children. Is

Crank

Jonathan is not correct because it has to be a trait that is learned.

So in that case Jonathan has to say that this is not an inherited trait it is learned by most people.

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3 years ago

HELP ASAP I WILL GIVE BRAINLIEST

alina1380 [7]

Answer:

it can last for 30 minutes

Explanation:

because it is very good at giving off heat, extothermal heat can last for quite a while.

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2 years ago

How many atoms are in 10.1 g Ne

LekaFEV [45]

Answer:

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

<u>Atomic Structure</u>

Reading a Periodic Tables
Moles

<u>Stoichiometry</u>

Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

[Given] 10.1 g Ne

[Solve] atoms Ne

<u>Step 2: Identify Conversions</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne

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3 years ago

In an acid-base neutralization reaction 38.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution.

DaniilM [7]

Answer:

0.2 M.

Explanation:

For the acid-base neutralization, we have the role:

The no. of millimoles of acid is equal to that of the base at the neutralization.

<em>∴ (XMV) KOH = (XMV) H₂SO₄.</em>

X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),

M is the molarity.

V is the volume.

For KOH:

X = 1, M = 0.5 M, V = 38.74 mL.

For H₂SO₄:

X = 2, M = ??? M, V = 50.0 mL.

∴ M of H₂SO₄ = (XMV) KOH/(XV) H₂SO₄ = (1)(0.5 M)(38.74 mL)/(2)(50.0 mL) = 0.1937 M ≅ 0.2 M.

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3 years ago