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Igoryamba
1 year ago
13

The liquid iodomethane has a density of 2.28 g/mL at 20.0°C. If a 109 gram sample of this compound is needed, what volume of the

liquid at 20.0°C must be provided?
Chemistry
1 answer:
stepladder [879]1 year ago
6 0

FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF

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Answer:

I would say the purple one!

Explanation:

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A 5.50 gram sample of C2H6 gas has a volume of 2.50 L. If the sample is at 41.20C, what will it’s pressure be?
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3 years ago
A 251 ml sample of 0.45M HCl is added to 455 mL of distilled water. What is the molarity of the
Oksi-84 [34.3K]

<u>We are given:</u>

251 mL sample of 0.45M HCl added to 455 mL distilled water

<u>Whack a mole! (finding the number of moles):</u>

We know that in order to find molarity, we use the formula:

Molarity = number of moles / Volume (in L)

so, number of moles is:

Number of moles = Molarity * Volume(in L)

now let's plug the values for the HCl solution to find the number of moles

Number of moles = 0.45M * 0.251 L

Number of moles = 0.113 moles

<u>Time to concentrate (finding the final concentration):</u>

Total final volume = 251 mL + 455 mL = 706 mL = 0.706 L

Number of moles of HCl = 0.113 moles

Molarity = Number of moles / Volume (in L)

Molarity = 0.113 / 0.706

Molarity = 0.16 M

___________________________________________________________

<u>BONUS METHOD TIME!!!</u>

We know the relation:

M1 * V1 = M2 * V2

where M1 and M2 are the initial and final molarities and V1 and V2 are initial and final volumes respectively

notice that I didn't mention that the volume has to be in Liters, that's because of the units being concerned with both sides of the equation, say I have the volume in mL and want to convert both these volumes to L, I would divide both sides by 1000, which would NOT change the overall value

Now, plugging values in this equation

(0.45) * (251) = (251 + 455)* (M2)

112.95 = (706)(M2)

M2 = 112.97/706                                [dividing both sides by 706]

M2 = 0.16 Molar

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