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2 years ago

8

If you had a mixture that was found to contain 1.05g SiO2, 0.69g Cellulose and 1.82g Calcium Carbonate. What percentage calcium

carbonate is in the mixture?

1 answer:

boyakko [2]2 years ago

6 0

Percentage by mass = (mass of substance / total mass) x 100
= 1.82 / (1.05 + 0.69 + 1.82) x 100
= 51.1% if Calcium Carbonate

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