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ANTONII [103]
3 years ago
8

If you had a mixture that was found to contain 1.05g SiO2, 0.69g Cellulose and 1.82g Calcium Carbonate. What percentage calcium

carbonate is in the mixture?
Chemistry
1 answer:
boyakko [2]3 years ago
6 0
Percentage by mass = (mass of substance / total mass) x 100
= 1.82 / (1.05 + 0.69 + 1.82) x 100
= 51.1% if Calcium Carbonate
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