Answer:
B
Explanation:
For solving this we need a heat balance

By changing the corresponding relations, we have

By cancelling similar factor, we obtain

Which means that the change of temperature in A is twice the change of B
Examination by a test; experiment, as in chemistry, metallurgy, etc.
Answer:
it can occur between hydrogen and 3 other elements
Explanation:
These elements are:
Nitrogen
Oxygen
Flourine
Answer:
Moles of NaCl formed is 6.0 moles
Explanation:
We are given the equation;
2 Na(s) + Cl₂(g) → 2 NaCl(s)
- Moles of Na is 6.0 moles
- Moles of Cl₂ is 4.0 moles
From the reaction;
2 moles of sodium reacts with 1 mole of chlorine gas to form 2 moles of NaCl
In this case;
6 moles of Na would require 3 moles of Cl₂, this means that chlorine gas is in excess.
Thus, the rate limiting reagent is sodium.
But, 2 moles of sodium reacts to form 2 moles of NaCl
Therefore;
Moles of NaCl = Moles of Na
= 6.0 moles
Thus, moles of sodium chloride produced is 6.0 moles
Sugar burns and turns black. A completely new substance was formed, which is the main pointer for it being a chemical reaction. More evidence would be change of color, odor, and the fact that flammability is a chemical property so setting something on fire would be a chemical change.