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Free_Kalibri [48]
3 years ago
10

Gr) = 25 – 31 g(4) =

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer:

there is no equation expressed in your question.

if you meant g(r) = an equation with a variable, then you just plug in 4 in the variable to get g(4).

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Can You Please Help Me ​
Dmitriy789 [7]
3 and 1/2 can be rewritten as a fraction as 7/2.

7 can be written as 7/1.

When dividing by a fraction, simply multiply by the reciprocal.

7/2*1/7.

Then, cross multiply across the top.

7*1=7

2*7=14

So it's 7/14, which can be reduced to 1/2.
8 0
3 years ago
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13x+y=4 please help me on this!
expeople1 [14]

Answer: SO if you hv to solve for x then the answer is 4/13. And if you wanna solve for y then the answer is 4.

Step-by-step explanation: solve for x=

13x+y=4

13x+0=4

x=4/13

Solve for y=

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8 0
3 years ago
For the following​ case, assume that the population standard deviation is known and decide whether use of the​ z-interval proced
Ray Of Light [21]

Answer:

B. It is reasonable to use the? z-interval procedure in this case? since, although the sample is small? (size less than? 15), the variable under consideration is very close to being normally distributed.

Step-by-step explanation:

answer b is considered to be correct because we know that the population is normal and the standard deviation is known, which allows using the interval z, the answer A is not correct because although the option to use the interval z is given, which is correct, the large sample is not favored, the answer C and D are incorrect because they both reject the use of the z interval and in d it is further rejected that although there is a normal distribution the sample is not, which is false

8 0
3 years ago
F(x) = 4x^2+2x+6 what is the discriminant of f? How many distinct real number zeros does f have?
Sunny_sXe [5.5K]

Answer:

The discriminant of f is 92, and it has no real zeros

Step-by-step explanation:

The discriminant of a quadratic is b^2-4ac, where the quadratic is in the form ax^2+bx+c. The discriminant of this one is therefore:

2^2-4(4)(6)=4-96=-92

Since the square root of a negative number is imaginary, this quadratic has no real number zeros. Hope this helps!

8 0
3 years ago
I can not figure out how to do this question and I need help please
spayn [35]
\bf \textit{quadratic formula}\\\\

\begin{array}{lcclll}
1x^2&-6x&+12&=0\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}
\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}
6 0
3 years ago
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