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kirza4 [7]
3 years ago
15

A Ping-Pong ball has a mass of 2.3 g and a terminal speed of 9.3 m/s. The drag force is of the form bv2 What is the value of b?

Physics
1 answer:
Fed [463]3 years ago
6 0

Answer:

The value is  b  =  0.00026 \ kg / m

Explanation:

From the question we are told that

   The mass of the  Ping-Pong is  m  =  2.3 \  g = 0.0023 \  kg

    The terminal  speed is  v  =  9.3 \  m/s

    The drag force is  bv^2

Generally the resultant force on the Ping- Pong is mathematically represented as

      F =  mg  -  bv^2

when  terminal velocity is  attained  , the resultant force is zero  so

      0 =  mg  -  bv^2

=>   b  =  \frac{m *  g}{v^2}

=>    b  =  \frac{0.0023 *  9.8}{ 9.3 ^2}

=>    b  =  0.00026 \ kg / m

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