Question

A Ping-Pong ball has a mass of 2.3 g and a terminal speed of 9.3 m/s. The drag force is of the form bv2 What is the value of b?

Answer 1

Answer:

The value is  $b = 0.00026 \ kg / m$

Explanation:

From the question we are told that

   The mass of the  Ping-Pong is  $m = 2.3 \ g = 0.0023 \ kg$

    The terminal  speed is  $v = 9.3 \ m/s$

    The drag force is  $bv^2$

Generally the resultant force on the Ping- Pong is mathematically represented as

      $F = mg - bv^2$

when  terminal velocity is  attained  , the resultant force is zero  so

      $0 = mg - bv^2$

=>   $b = \frac{m * g}{v^2}$

=>    $b = \frac{0.0023 * 9.8}{ 9.3 ^2}$

=>    $b = 0.00026 \ kg / m$