Answer:
1.5 hr
16.7
Explanation:
Zero apparent weight means there's no normal force.
Sum the forces in the centripetal direction.
∑F = ma
mg = mv²/r
v = √(gr)
v = √(7.4×10⁶ m × 10 m/s²)
v = 8602 m/s
The circumference of the equator is:
C = 2πr
C = 2π (7.4×10⁶ m)
C = 4.65×10⁷ m
So the period is:
T = C / v
T = (4.65×10⁷ m) / (8602 m/s)
T = 5405 s
T = 1.5 hr
The initial speed is:
v = C / T
v = (4.65×10⁷ m) / (25 h × 3600 s/h)
v = 517 m/s
The speed increases by a factor of:
8602 m/s / 517 m/s
16.7
vf² = vi² + 2ad
vf = vi +at
vf = final velocity
vi = initial velocity
decelerated = a = - (negative)
a. stop ⇒ vf = 0
vf = vi+at
0 = 20 - 1.5t
1.5t=20
t = 13.3 s
b. vi = 20 m/s
0 = 20² - 1.5d
1.5d = 20²
1.5d = 400
d =266.67 m
c. d = vi.t -1/2at²
d = 20.3 - 1/2.1.5.3²
d = 53.25 m
The formula for the torque is
<span>τf = p F
where
</span><span>τf is the torque
p is the distance where the force is applied by the tendon
F is force applied by the tendon
If there are given values, substitute in the equation and solve for the torque.</span>
what is a meteorite?
space debris that enters earth's atmosphere
space debris that reaches earth's surface
debris that is floating in space
space debris that make a fireball in earths's atmosphere
