At 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the state's eighth graders on this exam is more than 280.
<h3>How to state hypothesis conclusion?</h3>
We are given;
Sample size; n = 78
population standard deviation σ = 37
Sample Mean; x' = 280
Population mean; μ = 287
The school administrator declares that mean score is more (bigger than) 280. Thus, the hypotheses is stated as;
Null hypothesis; H₀: μ > 280
Alternative hypothesis; Hₐ: μ < 280
This is a one tail test with significance level of α = 0.13
From online tables, the critical value at α = 0.13 is z(c) = -1.13
b) Formula for the test statistic is;
z = (x- μ)/(σ/√n)
z = ((280 - 287) *√78 )/37
z = -1.67
c) From online p-value from z-score calculator, we have;
P[ z > 280 ] = 0.048
d) The value for z = -1.67 is smaller than the critical value mentioned in problem statement z(c) = - 1.13 , the z(s) is in the rejection zone. Therefore we reject H₀
e) We conclude that at 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the state's eighth graders on this exam is more than 280.
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Answer:
it's 4488 Wich would make 187
Because there was a pay rise, we can write the equation as x+0.04x = 24.492 and solve for x.
x+0.04x = 24.492
1.04x = 24.492
x=23.55
His original pay was £23.55
B is definatly the correct answer, Add all of the prices, and that is what it costs per sweatshirt
Answer:
Absolute difference between the medians = 0.35
Step-by-step explanation:
After arranging Q in ascending order excluding s, we get
Q = {1.1, 1.4, 1.7, 2.1, 2.3}
Here, the median is 1.7 ( The middlemost value is the required median.)
Now, if s < 1.7,
Q= {1.1, s, 1.4, 1.7, 2.1, 2.3}
Now for the least value, median = 1.55
If s > 1.7,
Q = {1.1, 1.4, 1.7, 2.1, s, 2.3}
Now for the greatest value, median = 1.9
Absolute difference between the medians = |1.9 -1.55|
= 0.35
