Answer:
Answer: Third option is the right answer.
Step-by-step explanation:
First we the write the expression
Now teacher says that the product of these polynomials will result in the sum of 
Now the teacher ask if we put the value of a = 2x and b = 1 then what will be the expression look like.
![(2x+1)\left [ (2x)^{2}+(1^{2})-(2x)(1)\right ]](https://tex.z-dn.net/?f=%282x%2B1%29%5Cleft%20%5B%20%282x%29%5E%7B2%7D%2B%281%5E%7B2%7D%29-%282x%29%281%29%5Cright%20%5D)
=
So third option is looking like our expression.
Hey there find an image attached..
Answer: see below
Step-by-step explanation:
(i)
200/2 = 100
Find 100 on cumulative frequency and the correspinding time: 14 minutes. So the answer is 14 minutes.
(ii)
First, find the lower quartile —> 200/4 = 50
Upper quartile —> 200/(3/4) = 150
Find the difference: 150 - 50 = 100
So the interquartile range is 100
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(-2x^3 +x -5) * (x^3 -3x)
= x^6*(-2*1) +x^4*(-2*-3 +1*1) +x^3*(-5) +x^2*(-3) +x(-5*-3)
= -2x^6 +7x^4 -5x^3 -3x^2 +15x
Ksjdhrisgdfbvgigsdtr aerigtksjdbfkhg is the correct answer
idk
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