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nekit [7.7K]
2 years ago
14

What is the range and domain?

Mathematics
1 answer:
ololo11 [35]2 years ago
8 0

Answer:

Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis.

Step-by-step explanation:

The range is the set of possible output values, which are shown on the y-axis.

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Can anyone help me in this whole math question? Especially Number b and c. <br>Thanks. ​
Bogdan [553]

Answer:

Irregular polygons are polygons that do not have equal sides or equal angles. When finding the area of an irregular polygon, partition the polygon into smaller regular polygon shapes. You can then plug those measurements into their respective area formulas and multiply to find the area of one part of the shape.

This is 16cm.

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3 years ago
Explain how units of length and capacity are similar in the metric system. please help!
kiruha [24]
The metric system is another system of measurement used to describe an objects capacity
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3 years ago
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Algebra:<br> simplify<br> 4y-6(5z-2y)-2z
gladu [14]

Answer:

16y−32z

Step-by-step explanation:

:D

6 0
3 years ago
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Given triangle ABC with m M
sammy [17]

9514 1404 393

Answer:

  49°

Step-by-step explanation:

The sum of angles in a triangle is 180°.

  ∠A +∠B +∠C = 180

  (x +32) +(x +41) +(3x +22) = 180 . . . . angles assumed to be in degrees

  5x +95 = 180

  5x = 85

  x = 17

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6 0
3 years ago
What is the equation of the circle with center (-3,1) that passes through the point (-5, 3)?
Natali5045456 [20]

Answer:

Option B) (x + 3)^2 + (y – 1)^2 = 8 is the correct answer.

Step-by-step explanation:

The equation of a circle with center (h,k) and radius r is given by:

(x-h)^2 + (y-k)^2 = r^2

Given

Center = (h,k) = (-3,1)

=> h = -3

=> k = 1

The distance between the center of circle and the point through which the circle passes will be the radius.

The distance formula is given by:

r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Given

(x_1,y_1) = (-3,1)\\(x_2,y_2) = (-5,3)

Putting the values in the formula

r = \sqrt{(-5+3)^2+(3-1)^2}\\r = \sqrt{(-2)^2+(2)^2}\\r = \sqrt{4+4}\\r = \sqrt{8}

Putting the values of h,k and r in general form of equation

\{x-(-3)}^2\} +(y-1)^2 = (\sqrt{8})^2\\(x+3)^2+(y-1)^2 = 8

Hence,

Option B) (x + 3)^2 + (y – 1)^2 = 8 is the correct answer.

4 0
3 years ago
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