Matter is anything that "has mass and takes up space" or option B. Matter is everything, it does not need a physical state, it does not need two elements to combined chemically, and it also doesn't have to be important to human society. Mass has to have mass, and volume. Mass is the amount of weight a object has, and volume is how much space the object also has.
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Answer:
I think its use a Acceleration to speed up
This is a type of question that tests your ability to find the limiting reagent, or the component that first runs out in the reaction and limits the continuation of the reaction.
To start, begin by figuring out how many times each component can run the reaction. It takes three moles of H2 to run the reaction “once”, so with five moles of H2, you can run it 1.66 times.
It takes one mole of N2 to run the reaction “once”, so with three moles of N2, you can run it three times. This means that H2 is the limiting reagent (1.66 < 3), and N2 will have excess.
After the reaction is run to completion (1.66 times), 1.33 moles of N2 will remain (1.33 left + 1.66 used = 3, beginning).
The number of solid precipitate that will be formed is 37.08 g
calculation
write the equation for reaction
=Hg(NO3)2 +Na2SO4 = HgSO4(s) +2NaNO3(aq)
find the moles of each reactant
moles ofHg(NO3)2=126.27/324.6= 0.389 moles
moles of Na2SO4=17.796/142=0.125 moles
NaSO4 is the limiting reagent and by use of mole ratio of NaSO4:HgSO4 which is 1:1 therefore the moles of H2SO4 is also= 0.125 moles
mass HgSO4=moles x molar mass
=0.125 x296.65= 37.08g
Answer:
0,07448M of phosphate buffer
Explanation:
sodium monohydrogenphosphate (Na₂HP) and sodium dihydrogenphosphate (NaH₂P) react with HCl thus:
Na₂HP + HCl ⇄ NaH₂P + NaCl <em>(1)</em>
NaH₂P + HCl ⇄ H₃P + NaCl <em>(2)</em>
The first endpoint is due the reaction (1), When all phosphate buffer is as NaH₂P form, begins the second reaction. That means that the second endpoint is due the total concentration of phosphate that is obtained thus:
0,01862L of HCl×= 1,862x10⁻³moles of HCl ≡ moles of phosphate buffer.
The concentration is:
= <em>0,07448M of phosphate buffer</em>
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I hope it helps!