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3 years ago

why can scientists ignore the forces of attraction between particles in a gas under ordinary conditions

1 answer:

8 0

The forces of attraction between particles in their gaseous state seems to be nonexistential.
therefore scientist would care less. however another state after gas which is plasma has a lesser force of attraction than the gaseous state.

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Solid aluminum (AI) and oxygen (O_2) gas react to form solid aluminum oxide (Al_2O_3). Suppose you have 7.0 mol of Al and 9.0 mo

Nimfa-mama [501]

Answer:

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

Explanation:

Step 1: Data given

Numbers of Al = 7.0 mol

Numbers of mol O2 = O2

Molar mass of Al = 26.98 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

4Al(s) + 3O2(g) → 2Al2O3(s)

Step 3: Calculate limiting reactant

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

Al is the limiting reactant, it will be consumed completely (7 moles).

O2 is in excess. There will react 3/4 * 7 = 5.25 moles

There will remain 9-5.25 = 3.75 moles

Step 4: Calculate moles Al2O3

For 4 moles Al we'll have 2moles Al2O3

For 7.0 moles of Al we'll have 3.5 moles of Al2O3 produced

Step 5: Calculate mass of Al2O3

Mass Al2O3 = moles Al2O3 * molar mass Al2O3

Mass Al2O3 = 3.5 moles* 101.96 g/mol

Mass Al2O3 = 356.9 grams

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

3 0

3 years ago

Write the chemical equation for the dissolution reaction of solid iron(iii) hydroxide in water. include the phases of all specie

Allushta [10]

When solid <span>iron (iii) hydroxide is dissolved into water, it ionizes or it dissociates into ions. These ions are the iron (iii) ions and the hydroxide ions. Iron(III) oxide is classified as a base when in aqueous solution since it produces hydroxide ions. It is a weak base so it does not completely dissociate into the solution. The dissociation equation would be:

Fe(OH)3 <-----> Fe3+ + OH-

To write a complete reaction, the reaction should be balanced wherein the number of atoms of each element in the reactant side and the product side should be equal. Also, the phases of the substances should be written. We do as follows:

</span>
Fe(OH)3 (s) <-----> Fe3+ (aq) + 3OH- (aq)

4 0

3 years ago

How many grams of iron oxide, Fe2O3 will be produced if 165 g of O2 gas is supplied? (follow the same steps as mol to mol, only

forsale [732]

Answer:

$m_{Fe_2O_3}=549gFe_2O_3$

Explanation:

Hello there!

In this case, according to the given chemical reaction for this problem about stoichiometry:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

Whereas there is a 3:2 mole ratio of oxygen (molar mass = 32.0 g/mol) to iron (III) oxide (molar mass = 159.69 g/mol) and therefore, the correct stoichiometric setup is:

$m_{Fe_2O_3}=165gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molFe_2O_3}{3molO_2} *\frac{159.69gFe_2O_3}{1molFe_2O_3} \\\\m_{Fe_2O_3}=549gFe_2O_3$

Regards!

8 0

3 years ago

The cavity within a copper [β = 51 × 10-6 (C°)-1] sphere has a volume of 1.220 × 10-3 m3. Into this cavity is placed 1.100 × 10-

juin [17]

Answer:

Δ should be 0.1009

Explanation:

The change in the units volume when temperature change can be expressed as:

∆v = v0Δ

with v0 = the initial volume

with = the volumetric temperature expansion coefficient

with Δ = the change of temperature.

To calculate the final volume vf we'll get:

v = v0 + ∆ = v0(1 + Δ)

The liquid just begins to spill out if v(benzene) = :

v()(1 + Δ) = = v() (1 + Δ)

(v(cavity)-v(benzene))/(((benzene) -(copper)) = Δ

((1.22*10^-3)-(1.1*10^-3))/((1240*10^-6)-(51*10^-6)) = Δ

Δ = 0.1009

Δ should be 0.1009

5 0

4 years ago

How many minutes are in 230 seconds?

DIA [1.3K]

Answer:

230 Seconds = 3.83333333 Minutes

Explanation:

8 0

3 years ago

Read 2 more answers