Answer:
Hydrogen has only 1 valence electron in its outermost shell.
Explanation:
Answer:
Work done on the system is zero , hence no work is done since the process is <u>isochoric.</u> There is no work done if the volume remains unchanged. (Though the temperature rises, work is only accomplished when the volume of the gas changes.)
Explanation:
ISOCHORIC PROCESS - An isochoric process, also known as a constant-volume process, isovolumetric process, or isometric process, is a thermodynamic process in which the volume of the closed system undergoing the process remains constant through the process. The heating or cooling of the contents of a sealed, inelastic container is an example of an isochoric process. The thermodynamic process is the addition or removal of heat, the closed system is established by the isolation of the contents of the container, and the constant-volume condition is imposed by the container's inability to deform. It should be a quasi-static isochoric process in this case.
<u>Hence , the work done in the system is zero.</u>
The molecules with the lowest viscosity
is the liquid with the least complex molecular structure. The structure affects
the viscosity of the fluid because they are less compact and can flow freely.
Answer: The molecular formula of the compound is 
Explanation:
Converting all these percentages into mass.
We take the total mass of the compound to be 100 grams, so, the percentages given for each element becomes its mass.So, the mass of each element is equal to the percentage given.
Mass of N = 30.45 g
Mass of O = 69.55 g
Step 1 : convert given masses into moles.
Moles of N=
Moles of O = 
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For N = 
For O =
The ratio of N: O = 1: 2
Hence the empirical formula is
.
Empirical mass of
is = 14(1)+16 (2)=46
The equation used to calculate the valency is:

Step 3: To calculate the molecular formula=
Hence, the molecular formula of the compound is 