Answer:
(a) There are outliers
(b) 
and 
Step-by-step explanation:
Given
Solving (a): Check for outliers
This is calculated using:
--- lower bound of outlier
--- upper bound of outlier
Where
So, we have:
The lower bound of outlier becomes
The upper bound of outlier becomes
So, we have:
--- the range without outlier
Given that:
--- This represents the lowest data
--- This represents the highest data
-24 and 64 are out of range of .
Hence, there are outliers
Solving (b): The outliers
The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)
So, the outliers are:
and
Answer:
18. 46
19. 0.7
22. 4 3/4
23. 54.5
26. 14
27. 11.5
31. 15
etc.
Step-by-step explanation:
absolute value means that the sign in front of the # doesn't matter, you just have to look at the positive value, for example:
absolute value of 46 = 46
absolute value of - 36 = 36
(imagine the sign in front of the # isn't there)
The ticket price of the item after applying coupon B first and then coupon A is $65.45
Coupons reduce the ticket price of an item.
<u><em>Ticket price</em></u><u><em> after </em></u><u><em>coupon B i</em></u><u><em>s applied </em></u>
An item costs $80. After applying the coupon B which gives, $3 off the price, the cost of the item reduces to $77 ($80 - $3).
The ticket price of the item after coupon B is applied is $77
<em><u>Ticket price </u></em><em><u>after c</u></em><em><u>oupon A </u></em><em><u>is applied </u></em>
The item costs $77 when coupon B is applied. If the discount is 15% off on coupon A, it means that the item costs 85%( 100 - 15%) of its initial price.
Ticket Price of the item = percentage price x price of the item after the first coupon B was applied
85% x $77
0.85 x $77 = $65.45
A similar question was solved here: brainly.com/question/17413216?referrer=searchResults
Answer it's a closed dot on positive 2 going to the left
Step-by-step explanation:
If u multiply the amount of gallons the pail holds by the amount of pails the tank can hold you would get 225.25 gallons.
