Answer:
there are two types of nomenclature used in organic system. the most widely used and universally accepted system of nomenclature is the IUPAC system of nomenclature. some compounds are referred to by their common name that existed before the IUPAC system or is more widely known than the IUPAC names.
Explanation:
IUPAC ( international union of pure and applied chemistry) system of nomenclature is used to name compounds in organic system. there are some principles to be followed while using this nomenclature. some of them are:-
1) identification of parent chain is the first step. the longest hydrocarbon chain is the parent chain.
2) identification of all the substituent groups of the parent chain is also required.
3) hydrocarbon cyclic ring has a fixed prefix and that is cyclo.
Answer:
There will be weight, there will be volume, there will be height
Explanation:
Answer:
1.4 mols
4th answer
Explanation:
22. 5 g of O2 in moles = (22.5/32) mols = 0.703 mol
The stoichiometry between O2 and H2O =1: 2
Therefore H2O produced = 2 * 0.703 mols=1.406 mols
Atoms cannot physically get more compact (temperature lowering increases the space between atoms) At absolute zero, the atoms are as physically close together as allowed by the physical laws governing it.
Answer:
The temperature of the gas is 876.69 Kelvin
Explanation:
Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P*V = n*R*T
where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.
In this case:
- P= 470 mmHg
- V= 570 mL= 0.570 L
- n= 0.216 g= 0.0049 moles (being the molar mass of carbon dioxide is 44 g/mole)
- R= 62.36367
Replacing:
470 mmHg*0.570 L= 0.0049 moles* 62.36367 *T
Solving:
T= 876.69 K
<em><u>The temperature of the gas is 876.69 Kelvin</u></em>