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grin007 [14]
3 years ago
5

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Chemistry
2 answers:
kirill [66]3 years ago
6 0
Well,





I guess the answer would be....


























.
WARRIOR [948]3 years ago
4 0

... hi gndjdbsgaisndbdhsjsbkdndkspanbbhdbdhdb

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Compounds usually have the same properties as the bonds they are made from true or false
gavmur [86]
Well , I will say this is a false statement.
This is because compounds which were all made by the same bond have same physical properties but different chemical properties.

Chemical Properties :
How do the subtances react with ( water, acid,alkaline, base , gas like oxygen, etc. )

Physical Properties :
- Solubility of those subtances in (water or organic solvent )
- Electric Conductivity
- Melting or Boiling Point
- Density
- Smell (exp : Ammonia has pungent smell , Esters has fruity smell)
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How do you label the delta E, on an energy diagram
vladimir1956 [14]
Delta energy on labelled diagram is attached below

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Help me for brainlest pleaes
Tresset [83]
First option.

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3 years ago
How many grams of propane, C3H8, are needed to make 140 grams of water?
Marizza181 [45]

Answer:

85.6 g

Explanation:

Step 1: Write the balanced combustion equation

C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O

Step 2: Calculate the moles corresponding to 140 g of H₂O

The molar mass of H₂O is 18.02 g/mol.

140 g × 1 mol/18.02 g = 7.77 mol

Step 3: Calculate the moles of C₃H₈ needed to produce 7.77 moles of H₂O

The molar ratio of C₃H₈ to H₂O is 1:4. The moles of C₃H₈ needed are 1/4 × 7.77 mol = 1.94 mol.

Step 4: Calculate the mass corresponding to 1.94 moles of C₃H₈

The molar mass of C₃H₈ is 44.10 g/mol.

1.94 mol × 44.10 g/mol = 85.6 g

7 0
3 years ago
For the reaction 2Na + Cl2 → 2NaCl, how many grams of chlorine gas are required to react completely with 57.5 mol of sodium?
Step2247 [10]

Answer:

1019.27 g.

Explanation:

  • For the balanced reaction:

<em>2Na + Cl₂ → 2NaCl,</em>

It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.

  • Firstly, we need to calculate the no. of moles of Cl₂ is needed to react with 57.5 mol Na:

2 moles of Na need → 1 mol of Cl₂, from the stichiometry.

57.5 moles of Na need → ??? mol of Cl₂.

<em>∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na =</em> (1 mol)(57.5 mol)/((2 mol) <em>= 28.75 mol.</em>

<em>∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂)(molar mass of Cl₂) =</em> (28.75 mol)(35.453 g/mol) <em>= 1019.27 g.</em>

4 0
3 years ago
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