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grin007 [14]
3 years ago
5

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Chemistry
2 answers:
kirill [66]3 years ago
6 0
Well,





I guess the answer would be....


























.
WARRIOR [948]3 years ago
4 0

... hi gndjdbsgaisndbdhsjsbkdndkspanbbhdbdhdb

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What happen when a piece of silver metal is added to the copper sulphate solution​
natta225 [31]

Answer:

Explanation:When silver Ag metal is added to copper sulphate CuSO4 solution, no reaction takes place as silver is less reactive than that of copper and cannot displace copper from its solution. Hence, when a piece of silver metal is added to copper sulphate solution there will be no reaction.

7 0
3 years ago
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The following unbalanced equation illustrates the overall reaction by which the body utilizes glucose to produce energy: C6H12O6
s344n2d4d5 [400]

Answer:

the conversion factor is f= 6  mol of glucose/ mol of CO2

Explanation:

First we need to balance the equation:

C6H12O6(s) + O2(g) → CO2(g) + H2O(l) (unbalanced)

C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) (balanced)

the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:

f = stoichiometric coefficient of CO2 in balanced reaction / stoichiometric coefficient of glucose in balanced reaction

f = 6 moles of CO2 / 1 mol of glucose = 6  mol of glucose/ mol of CO2

f = 6 mol of CO2/ mol of glucose

for example, for 2 moles of glucose the number of moles of CO2 produced are

n CO2 = f * n gluc = 6 moles of CO2/mol of glucose * 2 moles of glucose= 12 moles of CO2

3 0
4 years ago
PLZ HELP Question 14 of 25 What is the name for a representation of the physical world?
JulijaS [17]

Answer:

Model

Explanation:

A model of anything is something you make to represent it in it's physical world form

8 0
3 years ago
Name the type of equation shown here: 2NaBr+Ca(OH)2 —>CaBr2+2NaOH
sergeinik [125]
A) Double replacement
Because the reactants switch when they become products
6 0
3 years ago
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An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its
Aleks04 [339]

Answer:

T_1=-91.18\°C

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

\frac{T_1}{V_1}= \frac{T_2}{V_2}

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C

Best regards!

6 0
3 years ago
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