Answer:
1. 2(3x−2)(2x−3)
2. 3(3x+1)(2x+5)
3. 2(4x+1)(2x−5)
4. 4(2x+1)(2x+7)
5. 5(3x+1)(2x−5)
6. 3(3x−7)(2x+1)
7. 3(5x+3)(3x−2)
8. 2(7x−2)(2x−5)
9. 2(7x−3)(2x−3)
10. 4(5x−11)(2x+1)
11. 5(x−2)(x+12)
12. (x−1)(x−8)
15. x=1 or x=4
Step-by-step explanation:
1. Factor 12x2−26x+12
12x2−26x+12
=2(3x−2)(2x−3)
2. 3(3x+1)(2x+5)
3. Factor 16x2−36x−10
16x2−36x−10
=2(4x+1)(2x−5)
4. Factor 16x2+64x+28
16x2+64x+28
=4(2x+1)(2x+7)
5. Factor 30x2−65x−25
30x2−65x−25
=5(3x+1)(2x−5)
6. Factor 18x2−33x−21
18x2−33x−21
=3(3x−7)(2x+1)
7. Factor 45x2−3x−18
45x2−3x−18
=3(5x+3)(3x−2)
8. Factor 28x2−78x+20
28x2−78x+20
=2(7x−2)(2x−5)
9. Factor 28x2−54x+18
28x2−54x+18
=2(7x−3)(2x−3)
10. Factor 40x2−68x−44
40x2−68x−44
=4(5x−11)(2x+1)
11. Factor 5x2+50x−120
5x2+50x−120
=5(x−2)(x+12)
12. Let's factor x2−9x+8
x2−9x+8
The middle number is -9 and the last number is 8.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get -9
Multiply together to get 8
Can you think of the two numbers?
Try -1 and -8:
-1+-8 = -9
-1*-8 = 8
Fill in the blanks in
(x+_)(x+_)
with -1 and -8 to get...
(x-1)(x-8)
15. Let's solve your equation step-by-step.
(x−2)(x−3)=2
Step 1: Simplify both sides of the equation.
x2−5x+6=2
Step 2: Subtract 2 from both sides.
x2−5x+6−2=2−2
x2−5x+4=0
Step 3: Factor left side of equation.
(x−1)(x−4)=0
Step 4: Set factors equal to 0.
x−1=0 or x−4=0
x=1 or x=4
Sorry I wasn't able to do 13 and 14 but hope this helps! :)
Answer:
1) ∆BIG= ∆FAJ (i can't read it perfectly but i think these are the correct letters)
2)TNY
3) QWE(maybe F, cant read it perfectly)
4) VOR
5) AYD
6) GNH
7) MSE
8) TCA
9) ATE
Step-by-step explanation:
you need to look at the hashes, each segment that had one hash, is equivalent to the other segments with one hash, and so on. then you have to look and see which segments match on each shape. so let's say that if H is the same as A, and I is the same as B, and J is the same as C, then in ∆ HIJ, it would be equivalent to ∆ABC
Answer:
0.5
Step-by-step explanation:
sana panget kayong lahat