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Ahat [919]
3 years ago
7

Fast fast fast

Chemistry
1 answer:
alexdok [17]3 years ago
8 0
It’s number one because you add all of them together
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How many grams are in 6.53 moles of Pb
dezoksy [38]
Mr: 207.2
m=n×Mr= 6.53×207.2= 1353.02g
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The Resource Conservation and Recovery Act controls hazardous waste from its creation to its disposal. Please select the best an
o-na [289]

Answer:

True

Explanation:

Resource Conservation and Recovery Act (RCRA). 1976 of United States Environmental Protection Agency(EPA) empowers EPA to control the production, transportation, storage, treatment and disposal of hazardous waste. The RCRA act was amended in 1984 and 1986 to include Waste minimization along with appropriate disposal (not in the landfill site) and tackling of petroleum hazardous waste respectively along with other waste.

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3 years ago
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What is 11/6 + 11/6 in fractions
Andreyy89
3 2/3 is your answer
6 0
3 years ago
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4 b + 3 o2 → 2 b2o3 if 8 moles of b and 4 moles of o2 are allowed to react, how many moles of b2o3 can be formed?
raketka [301]

The number of moles of  b2o3 that will be formed is determined as 4 moles.

<h3>Limiting reagent</h3>

The limiting reagent is the reactant that will be completely used up.

4 b + 3O₂ → 2b₂O₃

from the equation above;

4 b ------------> 2 b₂O₃

2b ------------> b₂O₃

2 : 1

3O₂  -------------> 2b₂O₃

3  :  2

b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;

4 b ------------> 2 moles of  b2o3

8 moles -------> ?

= (8 x 2)/4

= 4 moles

Thus, the number of moles of  b2o3 that will be formed is determined as 4 moles.

Learn more about limiting reactants here: brainly.com/question/14222359

#SPJ1      

6 0
2 years ago
What is the empirical formula of a compound with a % composition of 40.1% sulfur and 59.9% oxygen?
olga_2 [115]

Answer:

The empirical formula is SO

Explanation:

The empirical formula of a chemical compound is the simplest positive integer ratio of atoms present in a compound.

Given 40.1% Sulphur and 59.9% oxygen.

We have to assume the mass of the compound to make our calculations easy.

Let's assume that the mass of the compound is 100g, that the mass of sulphur will be 40.1g and the mass of oxygen will then be 59.9g.

Number of moles= reacting mass/ molar mass

Molar mass of Sulphur = 32g/mol

Molar mass of Oxygen = 16g/mol

No of moles of S= 40.1g/100g

=0.401 moles of S

No of moles of O = 59.9g/100g

=0.599 moles of O

•These are the relative mole ratios for the compound,

•They need to be converted from decimals into whole numbers

•Turn mole ratio into whole number ratio by dividing by all the elements by the least/smallest number of moles calculated.

Number of moles of S = 0.401moles/0.401 = 1 mol S

Number of moles of O = 0.599moles/0.401 = 1.49 mol O which is approximately 1 (to the nearest whole number, considering it tenths' value which is 4 and less than 5)

The empirical formula is therefore SO.

4 0
4 years ago
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