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Gnoma [55]
3 years ago
6

An artery with cross sectional area of 1 cm2 branches into 20 smaller arteries each with 0.5 cm2 cross sectional area. If the ve

locity of blood in the thicker artery is v, what is the velocity of the blood in the thinner arteries
Physics
1 answer:
kow [346]3 years ago
4 0

Answer:

The velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

Explanation:

To find the velocity of the blood we need to use the continuity equation:

n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2}   (1)  

<u>Where</u>:

n: is the number of branches

A: is the cross-sectional area

v: is the velocity

For artery 1, we have:

n₁ = 1, A₁ = 1 cm², v₁ = v

For the 20 arteries (2), we have:

n₂ = 20, A₂ = 0.5 cm², v₂ =?

By using equation (1):

n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2}

1 cm^{2}*v = 20*0.5 cm^{2}*v_{2}

v_{2} = \frac{1 cm^{2}*v}{20*0.5 cm^{2}} = \frac{v}{10} = 0.1v

Therefore, the velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

I hope it helps you!      

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goldfiish [28.3K]

Answer:

0.912

Explanation:

Given that

Height of bouncing of the ball, h = 1.71 m

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Height from which the ball was dropped, H = 2.47

First, let's start by defining what coefficient of restitution means

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1.71 = 2.47 * c^4, where c = CoR

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3 years ago
A 1200 kg car passes traffic light at a velocity of 10.2 m/s to the north and accelerates at a rate of 2.45 m/s^2. Calculate the
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The car’s momentum after 4.21s is 24617.4 kgm/s

<h3>Newton's Second Law of Motion.</h3>

Newton's second law state that, the rate of change of momentum, is directly proportional to the applied force.

Given that a 1200 kg car passes traffic light at a velocity of 10.2 m/s to the north and accelerates at a rate of 2.45 m/s^2. To calculate the car’s momentum after 4.21 s, Let us first list all the parameters involved.

  • Velocity u = 10.2 m/s
  • Acceleration a =  2.45 m/s²
  • Mass m = 1200Kg
  • Time t = 4.21 s

From Newton's second law,

F = (mv - mu) / t

ma = (mv - mu) / t

Substitute all the parameters into the formula above.

1200 × 2.45 = ( mv - 1200 × 10.2 ) / 4.21

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Cross multiply

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Make mv the subject of the formula

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Therefore, the car’s momentum after 4.21s is 24617.4 kgm/s

Learn more about Momentum here: brainly.com/question/25121535

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