They look like tiny cubes. They are in a cubic form.
Use the formula: <span><span><span><span>P1</span><span>V1</span></span><span>T1</span></span>=<span><span><span>P2</span><span>V2</span></span><span>T2</span></span></span>
We know that we want <span><span>P1</span>=<span>P2</span></span> so the pressure will remain constant, so we can say that: <span><span><span><span>P1</span><span>V1</span></span><span>T1</span></span>=<span><span><span>P1</span><span>V2</span></span><span>T2</span></span></span>
Plug in the values we know: <span><span><span><span>P1</span>⋅0.250L</span><span>283K</span></span>=<span><span><span>P1</span>⋅0.285L</span><span>T2</span></span></span>
(Remember that temperature must be done in Kelvin.)
Cross multiply: <span><span>T2</span>⋅<span>P1</span>⋅0.250L=283K⋅<span>P1</span>⋅0.285L</span>
Divide both sides by <span>P1</span>.
<span><span>T2</span>⋅0.250L=283K⋅0.285L</span>
<span><span>T2</span>=<span><span>283K⋅0.285L</span><span>0.250L</span></span></span>
<span><span>T2</span>=323K</span>
(This is also <span>50˚C</span>.)
The temperature of the river downstream of the nuclear power plant will be 53.3 degrees f
Answer:
Explanation:
You could try to say how helpful they are what they are and what they do
A ) A range:
R = v² sin 2 α / g
The maximum range is when sin 2 α = 1, or when: 2 α = 90°
α = 45°
B ) R = 27.5² · 1 / 9.81 = 77 m
C ) Time:
T = 2 v sin α / g = 2 · 27.5 · sin 45° / 9.81 =
= 2 · 27.5 · 0.7 / 9.81 = 3.92 s
