In a rational function, holes are located where f(x) is undefined(the denominator is 0), but the undefined points can be factored out. In f(x), when x is 4 or -3, f(x) is undefined. But, x+3 can be factored out, so it is a hole. The hole is located at (-3,-1/7)
Hello!

Recall that:
is equal to
. Therefore:
![\sqrt[3]{x^{2} } = x^{\frac{2}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%20%7D%20%3D%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:

36/100 is 9/25 in simplest form
The reciprocal should be the number flipped...
in this case..

is the reciprocal.
Answer:
So, the prime factorisation of 24 are 2 × 2 × 2 × 3 or 23 × 3, where 2 and 3 are the prime numbers.
Step-by-step explanation:
Hope it helps!