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AVprozaik [17]
3 years ago
13

I need help and I dont get this at all

Mathematics
1 answer:
mel-nik [20]3 years ago
4 0

Answer:

The sides form a <u>right triangle</u>

Step-by-step explanation:

\sqrt(130)km = 11.4 km

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HELP !!!! picture is shown GEOMETRY
kenny6666 [7]
The right triangle is also Isosceles. It has two equal angles of 45°.

(hypotenuse)² = 2S²

4 = 2S² => S = √2

Therefore B is the correct answer.
8 0
3 years ago
How do you get statistics from percentages
Nikitich [7]

Answer:

Divide the target demographic by the entire population, and then multiply the result by 100 to convert it to a percentage.  

Step-by-step explanation:

Gather Your Statistics.

Divide by Entire Population.

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6 0
3 years ago
What are the zeros of f(x)=x(x-8)
Flura [38]

Answer:

The zeros are x=0,x=8

Step-by-step explanation:

f(x)=x(x-8)

To find the zeros, we set the equation equal to zero

0 = x(x-8)

Using the zero product property

x= 0  x-8=0

x=0  x=8

The zeros are 0,8

8 0
3 years ago
Read 2 more answers
If f(3)=2x^3 -2 , what is the value of f(2)
iris [78.8K]

I'm not sure about this but will give it a try:

Let f(n) = 2xⁿ - 2

Then f(3) = 2x³ - 2

So, f(2) = 2x² - 2

5 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)
trapecia [35]

\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y = 1340 \:  \:  \:  \:  \: (3)

Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 1080 \div 24

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 45

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:90 + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 260 - 90

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 170

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 170 \div 10

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 17

Hence, each van can carry (y) = 17 students in total.

5 0
3 years ago
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