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Ray Of Light [21]

2 years ago

7

Terry has 3 pairs of pants (black, khaki, and brown) and 4 shirts (yellow, red, blue, and white). He does not care which colors

he wears together. How many different outfits can Terry make

1 answer:

belka [17]2 years ago

3 0

Answer:

0 is the answer

Step-by-step explanation:

because colour are not pants or shirt put me in brainlist

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Which expressions are equivalent to the one below? check all that apply :)

svlad2 [7]

Since 5=15/3

5^x = (15/3)^x = 15^x / 3^3

Choices A and D

4 0

3 years ago

Craig has a 6 ft by 6 ft square garden in his backyard. He wants to transform the garden into a rectangular shape and reduce the

Yanka [14]

X = 2
So 6 + 2 = 8
6 - 2 = 4
8 x 4 = 32

(6-x)(6+x) = 32
36 - x^2 = 32
-36. -36
-x^2 = -4
X = 2

7 0

3 years ago

From the foot of a building i have to look upwards at an angle of 22 degrees to sight the top of a tree. From the top of a build

shepuryov [24]

Answer:

i say b

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Consider f and c below. f(x, y, z) = yzexzi + exzj + xyexzk,

Jet001 [13]

Answer:

$f(x,y,z)=ye^{xz}+C$

Step-by-step explanation:

We can write the given expression as :

$\vec f(x,y,z)=yze^{xz}\,\vec\imath+e^{xz}\,\vec\jmath+xye^{xz}\,\vec k$

As given, f = ∇f.

∇f = $\dfrac{\partial f}{\partial x}i$ + $\dfrac{\partial f}{\partial y}j$ + $\dfrac{\partial f}{\partial z}k$

We can write the partial derivative with respect to x, y and z.

$\dfrac{\partial f}{\partial x}=yze^{xz}$ ___(Equation 1)

$\dfrac{\partial f}{\partial y}=e^{xz}$ ______(Equation 2)

$\dfrac{\partial f}{\partial z}=xye^{xz}$ ______(Equation 3)

Take equation 2 and integrate with respect to y,

$\dfrac{\partial f}{\partial y}=e^{xz}$

$f(x,y,z)=ye^{xz}+a(x,z)$ ----------Equation 4

Derivate both sides w.r.t x , we get :

$\frac{d}{dx}(yze^{xz})=yze^{xz}+\dfrac{\partial a}{\partial x}$

or

$\dfrac{\partial a}{\partial x}=0$

integrate

a(x,z)=b(z)

put in equation 4 ,

we get :

$f(x,y,z)=ye^{xz}+b(z)$

take derivative wrt z

$\frac{d}{dz} (ye^{xz}+b(z))\impliesxye^{xz}=xye^{xz}+\frac{db}{dz}$

we can take here:

$\frac{db}{dz} = 0$

integrate:

$\int\ {\frac{db}{dz} } \, =\int0$

b(z) = C

The function can be written as :

from equation 4 :

$f(x,y,z)=ye^{xz}+C$

Where C is a constant.

4 0

2 years ago

What is the propertys that i use in this i need th answer fast please and thanyous

Ivan

Distributive property

5 0

3 years ago