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dlinn [17]
3 years ago
15

What is the multiplier?A. 0.123B. 0.111C. 9D. 81​

Mathematics
1 answer:
amm18123 years ago
7 0

Answer:

it is eather d or b

Step-by-step explanation:

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The equation for the circle is (x-2)^2 + (y-1)^2 = 4<br><br> True<br> or<br> False???
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True because the center is (2,1) and radius is 2
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Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n? All integers where n ≥ 1 All integers where n &gt; 1
krok68 [10]

All integers where n ≥ 1.

We have given that the sequence,

a_{n} =4-3(n-1)

We have to find the domain for n.

<h3>What is the meaning of arithmetic sequence?</h3>

Arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means the second minus the first.

That is, a_{n} =a+(n-1)d

where a = first term of sequence.

d =common difference.

n =number of terms which belongs to natural numbers

By  the definition of arithmetic sequence n starts with 1

Remember that,the natural number starts with 1

Now, in given sequence  for nth term

a_{n} =4-3(n-1)

The domain for n is All integers where n ≥ 1.

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brainly.com/question/20118982

4 0
2 years ago
Find the area of the composite figure.
Tamiku [17]
Area =leagth x wigth
4 0
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7 0
3 years ago
Find four numbers that form a geometric progression such that the third term is greater than the first by 12 and the fourth is g
olchik [2.2K]

If x is the first number in the progression, and r is the common ratio between consecutive terms, then the first four terms in the progression are

\{x,xr,xr^2,xr^3\}

We want to have

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In the second equation, we have

xr^3-xr=xr(r^2-1)=36

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xr^2-x=x(r^2-1)=12

Substituting this into the second equation, we find

xr(r^2-1)=12r=36\implies r=3

So now we have

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Then the four numbers are

\left\{\dfrac32,\dfrac92,\dfrac{27}2,\dfrac{81}2\right\}

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