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Deffense [45]
3 years ago
12

What is the constant ​

Mathematics
1 answer:
vredina [299]3 years ago
8 0

Answer:

I have no clue but whatever it is it is

Step-by-step explanation:

puebes the knife go chop chop chop

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svp [43]
It is the first answer
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3 years ago
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Muhammad cashed a check from his uncle. He then spent $7.40 on taxis and $40.20 at the restaurant. He deposited the $97.75 he ha
ser-zykov [4K]
The amount he had left plus the two amounts he spent equal the total amount of the check. Add the three amounts together.

$97.75 + $40.20 + $7.40 = $137.95 + $7.40 = $145.35
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4 years ago
Write the equation in slope intercept form for the line that has a slope of -3 and y intercept of (0,5)
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The answer is y=-3x+5
8 0
4 years ago
En un acuario compraron 30 peces y 18 tortugas de agua. Los van a colocar en peceras. Cada una tiene que haber la misma cantidad
seraphim [82]

Answer:

a) ¿Cuántas peceras compraron?

Según el cálculo anterior, la cantidad de peceras que compró es de 90 peceras.

b) ¿Cuántos peces y tortugas puede tener cada tanque?

3 peces por tanque

5 tortugas de agua por tanque

Step-by-step explanation:

Resolvemos la pregunta anterior utilizando el cálculo de múltiplo común más bajo

En un acuario compraron 30 peces y 18 tortugas de agua.

Encuentre y enumere los múltiplos de cada número hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

El mínimo común múltiplo es el número de tanques

Múltiplos de 18:

18, 36, 54, 72, 90, 108, 126

Múltiplos de 30:

30, 60, 90, 120, 150

Por lo tanto,

MCM (18; 30) = 90

a) ¿Cuántas peceras compraron?

Según el cálculo anterior, la cantidad de peceras que compró es de 90 peceras.

b) ¿Cuántos peces y tortugas puede tener cada tanque?

El número de peces que puede tener cada tanque = Número de tanques / Número de peces

= 90/30

= 3 peces por tanque

El número de tortugas de agua que puede tener cada tanque =

Número de tanques / Número de tortugas de agua

= 90/18

= 5 tortugas de agua por tanque

5 0
3 years ago
Solve for a and b in the following circles:<br> A)
rjkz [21]

Given:

A quadrilateral inscribed in a circle.

To find:

The values of a and b.

Solution:

A quadrilateral inscribed in a circle. So, the quadrilateral is a cyclic quadrilateral.

We know that the sum of the opposite angles of a cyclic quadrilateral is 180 degrees.

a+79^\circ=180^\circ

a=180^\circ-79^\circ

a=101^\circ

We know that the measure of arc is twice of measure of subtended angle on that arc.

(110^\circ+b)=2(96^\circ)

110^\circ+b=192^\circ

b=192^\circ-110^\circ

b=82^\circ

Therefore, the value of a is 101 degrees and the value of b is 82 degrees.

7 0
3 years ago
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