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3 years ago

Maisie is exactly 135 weeks old. how many hours is this

Mathematics

2 answers:

Vinil7 [7]3 years ago

7 0

24 times 7 = 168 times 145 = 22, 680 hours

Licemer1 [7]3 years ago

5 0

$1 \: week = 7 \: days \\ 1 \: day = 24 \: hours \\ 135 \times 7 \times 24 = 22680$

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How do I do this problem?

Elenna [48]

Roots can be written as fraction exponents. An exponent of 1/2 means the square root.

$(12 x^{4})^{1/2} = \sqrt{12 x^{4} } \\ \\ \sqrt{12 x^{4} } = \sqrt{3*4*x^{2}*x^{2}} = 2x^{2} \sqrt{3}$

8 0

3 years ago

Need some help with this question please

Serggg [28]

Answer:

$\frac{15}{17}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ad}{hip} \\ \\ \sin( \alpha ) = \frac{op}{hip}$

Pythagorean theorem

hip² = op² + ad²

17² = x² + 8²

x² = 17² - 8²

$x \: = \sqrt{{17}^{2} - {8}^{2} } \\ x = \sqrt{289 - 64} \\ x = \sqrt{225} \\ x = 15$

$\sin( \alpha ) = - \frac{15}{17}$

$\sin( - \alpha ) = \frac{15}{17}$

4 0

3 years ago

Each year, all final year students take a mathematics exam. It is hypothesized that the population mean score for this test is 8

drek231 [11]

Answer:

95% Confidence interval: (96.06,103.94)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 85

Sample mean, $\bar{x}$ = 100

Sample size, n = 30

Alpha, α = 0.05

Population standard deviation, σ = 11

95% Confidence interval:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$100 \pm 1.96(\frac{11}{\sqrt{30}} ) = 100 \pm 3.94= (96.06,103.94)$

(96.06,103.94) is the 95% confidence interval for the population mean test score.

8 0

3 years ago

A particle is moving on a straight line in such a way that its velocity v is given by v ( t ) = 2 t + 1 for 0 ≤ t ≤ 5 where t is

Lady_Fox [76]

Answer:

The total distance traveled by the particle is S = 30.

Step-by-step explanation:

Given that velocity,

v(t) = 2t + 1

To find the total distance travel, we integrate the velocity function, v(t), to obtain the distance function s(t), and evaluate the resulting distance at the interval given. That is at t = 0 to t = 5.

Integrating v(t) with respect to t, we have

s(t) = t² + t + C.

At t = 5

s(5) = 5² + 5 + C

= 25 + 5 + C

= 30 + C

At t = 0

S(0) = 0 + 0 + C

= C

The required distance is now

S(5) - S(0)

= 30 + C - C

= 30.

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3 years ago

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maks197457 [2]

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3 0

3 years ago