Given: Mass m= 10 g convert to Kg m = 0.01 Kg Velocity V = 300 m/s
Required: Kinetic energy = K.E = 1/2 mV²
K.E = 1/2 (0.01 Kg)(300 m/s)²
K.E = 450 J
Answer:
One way to look at this is to consider the forces acting on any point in a string.
For a very small portion of string F = M a must still hold. As M approaches zero the small portion of string would have to approach infinite acceleration if the net force on that portion of string were not zero.
One generally considers the net force acting on the center of mass of an object not the individual forces acting on each infinitesimal mass composing
the object.
<h2><u>Answer:</u></h2>
As you are looking for a new tennis partner. People should keep in mind that they should go for the one who most likely demonstrate good sportsmanship
Luis, when you pursue the principles in tennis, you realize when to talk up, you don't blast a racquet or shout, holler.
Whatever it is following the principles and being respectful it the most ideal approach.
Answer:
y = 0m
y0 = 166m
v0y = 0 m/s
g = 9.8 m/s^2
t = ?
Solve for t:
y = y0 + v0y*t - (0.5)gt^2
0 = 166 - (0.5)(9.8)t^2
t = 5.82 s
Now, using time, we can solve for the range using the equation:
x = vx(t)
x = (40)(5.82)
x = 232.8 m
The impact horizontal component of velocity will be 40 m/s as velocity in terms of x is always constant. To find the impact vertical component of velocity, we use the equation:
v = v0y - gt
v = 0 - (9.8)(5.82)
v = -57.04 m/s
