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Katena32 [7]
4 years ago
6

How is the gravitational force related to the distance between two objects?

Physics
1 answer:
miss Akunina [59]4 years ago
7 0

gravitational force is inversely proportional to the square of the separation distance between the two interacting objects

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Fig. 2.1 shows a train
Vitek1552 [10]

Answer:

\mathrm{(a)\:}32,000,000\:\mathrm{Ns},\\\mathrm{(b)\:}390,000\:\mathrm{N}

Explanation:

The impulse-momentum theorem states the impulse on an object is equal to the change in momentum of that object. Momentum is given by p=mv. Since mass is constant, the train's change in momentum is:

\Delta p=m\Delta v=750,000\cdot42=31,500,000=\fbox{$32,000,000\:\mathrm{Ns}$}(two significant figures).

Impulse is also given as \Delta p = F\Delta t, where F is the average force applied and \Delta t is change in time. Since t is given as 80\mathrm{s}, we have the following equation:

F\Delta t=\Delta p\\\\F=\frac{\Delta p}{\Delta t},\\\\F=\frac{31,500,000}{80},\\\\F=393,750=\fbox{$390,000\:\mathrm{N}$}(two significant figures).

7 0
3 years ago
Is speed or velocity more helpful to a pilot?
Dima020 [189]
Velocity, as it is is a vector quantity, so it has both direction and magnitude.
Speed is a scalar quantity, so it only has magnitude, no direction.
3 0
3 years ago
Read 2 more answers
A steeper incline plane will require _____ Force​
ExtremeBDS [4]

Answer:

wind

Explanation:

8 0
3 years ago
Im stuck on number 4, am I just supposed to talk about theory because there is no given info.
Strike441 [17]

Explanation:

Assuming no air resistance, the horizontal acceleration at all points is 0, and the vertical acceleration at all points is -g (if near the surface of the Earth, -9.8 m/s²).

6 0
4 years ago
If an ocean wave passes a stationary point every 5 s and has a velocity of 10 m/s, what is the wavelength of the wave
Rainbow [258]

Answer:

As Per Provided Information

Velocity of wave v is 10m/s

These ocean wave passes a stationary point every 5 s ( It's time period)

First we calculate the frequency of ocean wave .

<u>Using</u><u> Formulae</u>

\blue{\boxed{\bf \:  \nu =  \cfrac{1}{v}}}

here

v is the velocity of wave .

\sf\longrightarrow \nu \:  =  \cfrac{1}{10}  \\  \\ \\  \sf\longrightarrow \nu \:  = 0.1Hz

Now calculating the wavelength of the wave .

<u>Using </u><u>Formulae </u>

\boxed{ \bf \lambda =  \cfrac{v}{ \nu}}

Substituting the value and we obtain

\sf \longrightarrow \lambda \:  =  \cfrac{10}{0.1}  \\  \\  \\ \sf \longrightarrow \lambda \:  =   \cancel\cfrac{10}{0.1}  \\  \\  \\ \sf \longrightarrow \lambda \:  =100m

<u>Therefore</u><u>,</u>

  • <u>Wavelength </u><u>of </u><u>the </u><u>wave </u><u>is </u><u>100 </u><u>metres</u><u>.</u>
8 0
3 years ago
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