Answer: 4 ohms
Explanation:
For parallel connection we use this formula
R=equivalent resistance
R1=24 ohms
R2=8 ohms
R3=12 ohms
1/R=1/R1 + 1/R2 + 1/R3
1/R=1/24 + 1/8 + 1/12
1/R=(1x1+3x1+2x1) ➗ 24
Cross multiplying we get
24x1=(1x1+3x1+2x1) x R
24=(1+3+2) x R
24=6xR
Divide both sides by 6
24 ➗ 6=6xR ➗ 6
4=R
R=4 ohms
Answer:
The distance and average speed are 54.79 m and 10.85 m.
Explanation:
Given that,
Speed = 21.7 m/s
Time = 5.05 s
(a). We need to calculate the distance
Firstly we will find the acceleration
Using equation of motion
Where, v = final velocity
u = initial velocity
t = time
Put the value in the equation
Now, using equation of motion again
For distance,
The distance is 54.79 m.
(b). We need to calculate the average speed during this time
Where, D = total distance
T = time
Put the value into the formula
Hence, The distance and average speed are 54.79 m and 10.85 m.
Answer:
<em>If the Universe holds enough matter, including dark matter, the combined gravitational attraction of everything will gradually halt this expansion and precipitate the ultimate collapse. Over time, galaxies, then individual stars, will smash into each other more frequently, killing off any life on nearby planets.</em>
Answer:
ρ=0.0102lbm/ft^3
Explanation:
To solve this problem we must take into account the equation of continuity, this indicates that the sum of the mass flows that enter a system is equal to the sum of all those that leave.
Therefore, to find the mass flow of exhaust gases we must add the mass flows of air and fuel.
m=0.59+60=60.59lbm/s( mass flow of exhaust gases)
The equation that defines the mass flow (amount of mass that passes through a pipe per unit of time) is as follows
m=ρVA
Where
ρ=density
V=velocity
m=mass flow
A=cross-sectional area
solving for density
ρ=m/VA
ρ=60.59/{(1485)(4)}
ρ=0.0102lbm/ft^3
