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borishaifa [10]
3 years ago
15

The speed of surface waves in water decreases as the water becomes shallower. Suppose waves travel across the surface of a lake

withn a speed of 2m/s and a wavelength of 1.5m. When these waves move into a shallower part of the lake, their speed decreases to 1.6m/s, though their frequency remains the same. Find the wavelength of the wave in the shallower water.
Physics
1 answer:
Elanso [62]3 years ago
7 0

Answer:

The correct solution is "1.2 m".

Explanation:

The given values are:

Wavelength of waves,

λ = 1.5 m

Speed of waves on surface,

V = 2 m/sec

Speed of waves in water,

V₁ = 1.6 m/sec

As we know,

⇒  V=f\times \lambda

or,

⇒  f=\frac{V}{\lambda}

On substituting the values, we get

⇒      =\frac{2}{1.5}

⇒      =1.33 \ Hz

hence,

⇒  \lambda_1=\frac{V_1}{f}

On substituting the values, we get

⇒       =\frac{1.6}{1.33}

⇒       =1.2 \ m

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3 years ago
Light in the air is incident at an angle to the surface of (12.0 A) degrees on a piece of glass with an index of refraction of (
Orlov [11]

The question is incomplete. You dis not provide values for A and B. Here is the complete question

Light in the air is incident at an angle to a surface of (12.0 + A) degrees on a piece of glass with an index of refraction of (1.10 + (B/100)). What is the angle between the surface and the light ray once in the glass? Give your answer in degrees and rounded to three significant figures.

A = 12

B = 18

Answer:

18.5⁰

Explanation:

Angle of incidence i = 12.0 + A

A = 12

= 12.0 + 12

= 14

Refractive index u = 1.10 + B/100

= 1.10 + 18/100

= 1.10 + 0.18

= 1.28

We then find the angle of refraction index u

u = sine i / sin r

u = sine24/sinr

1.28 = sine 24 / sine r

1.28Sine r = sin24

1.28 sine r = 0.4067

Sine r = 0.4067/1.28

r = sine^-1(0.317)

r = 18.481

= 18.5⁰

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Answer:

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Explanation:

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if we assume that the planet has a spherical shape,  the object mass at the surface is at a distance d=R (radius) from the centre of mass and the planet volume is V=4/3πR³ ,

since M= ρ* V = ρ* 4/3πR³ , ρ= density

F = G*m*M/R² = G*m*ρ* 4/3πR³/R²= G*ρ* 4/3πR

from Newton's second law

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Answer:

Explanation:  V = 3 cm/s = 0.03 m/s

                  BY THE FORmULA OF  K.E

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                     m = 300 x 2/0.0009

                       m= 666666.66kg

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